Answer:
26 g left undisolved which gives you the amount that would crystallize
Explanation:
Step 1: Data given
A solid mixture consists of 44.2g of KNO3 (potassium nitrate) and 7.8g of K2SO4 (potassium sulfate).
The mixture is added to 130. g of water
KNO3 has a solubility of 14 g solute/ 100 g water
Step 2: Calculate mass of KNO3 in 130 grams of water
X g of KNO3/ 130 g water= 14 g of KNO3/ 100 g water
X = 14*1300/100 = 18.2
X= 18.2 g (this is the amount of solute that dissolves at 0 degrees C in 130 g water)
Step 3: Calculate amount KNO3 that will crystallize
Of the 44.2g of KNO3 in 130 g of water at 0 degrees celsiusonly 18.2 can dissolve, this means:
44.2g - 18.2g = 26 g left undisolved which gives you the amount that would crystallize
