The approximate alcohol content is 210 ml.
Explanation:
It can be deduced from the question that each bottle is of 1000ml or 1 litre.
The first bottle is one half full means it has 500 ml of solution and it has 20% alcohol in it. So volume of alcohol in the solution is
20/100*500
=100 ml
The first bottle is one fifth full, so the volume of mixture is 1/5th of 1000ml
so it is 200ml having 30% alcohol
30/100*200
= 60 ml
The third bottle is one tenth full so its volume is 1/10*1000
100 ml. having 50% of alcohol
50/100*100
50 ml.
The alcohol content obtained from all these 3 litres is:
100+60+50
= 210 ml of alchohol is obtained from 800 ml of mixture.
240 g NaOH
<em>Step 1</em>. Calculate the moles of NaOH
Moles of NaOH = 0.750 L solution × (8 mol NaOH/1 L solution) = 6 mol NaOH
Step 2. Calculate the mass of NaOH
Mass of NaOH = 6 mol NaOH × (40 g NaOH/1 mol NaOH) = 240 g NaOH
The correct match are as follows:
Boyles Law is about a gas at constant temperature. Therefore, the correct match would be the volume of a gas varies inversely with pressure if the temperature is kept constant.
Charles Law would be that the volume of a gas varies directly with temperature if the pressure is kept constant.
Gay-lussac's law would be that the pressure of a gas varies directly with temperature if the volume is kept constant.
Answer:
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Answer:
Neutrons play no role in the net charge of an atom, so you can ignore them here.
Proton = 7
Electron = 10
Net Charge = 7 - 10
= -3
Again,
Proton = 3
Electron = 2
Net Charge = 3 - 2
= 1