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Sloan [31]
2 years ago
9

How many molecules are contained in 5.7 gms of CaCO3​

Chemistry
1 answer:
Dominik [7]2 years ago
8 0
100grams of caco3 contains full 6.022x10^23 molecules
So 5.7 will contain= 3.432x10^22
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Which pair of reactants will undergo aldol condensation to produce methylvinyl ketone?
xenn [34]

When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed <u> methyl vinyl ketone.</u>

<u />

In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.

In aldol condensation, when  formaldehyde and acetone then react with each other then it will be formed <u> </u><u>methyl vinyl ketone.</u>

It can be written as

CH_{2} O + CH_{3} COCH_{3} → HOCH_{2} -CH_{2} -CO-CH_{3}

When it will be heated then it gives methyl vinyl ketones.

HOCH_{2} -CH_{2} -CO-CH_{3} → CH_{2} =CH-CO-CH_{3}

So, the pair of reactants will be formaldehyde and acetone

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6 0
1 year ago
What element has an atomic mass 4?
Daniel [21]

Answer:

Helium has atomic mass  4.002602.

So the answer to yr question is helium.

4 0
3 years ago
Read 2 more answers
Why is it important to minimize the amount of oil released into the ocean?
Andrei [34K]
Because many animals are likely to die from contamination
6 0
3 years ago
Answer the amount of miles of O2
lord [1]

Answer:

3

Explanation:

the answer is 3 because it is 3 for the o2 so 3 you <em>have </em><em>to </em><em>pay </em><em>more </em><em>attention </em><em>for </em><em>the </em><em>small </em><em>ditails </em>

5 0
2 years ago
Liquid methanol (CH₃OH) can be used as an alternative fuel in pickup and SUV engines. An industrial method for preparing it invo
r-ruslan [8.4K]

40.6 kJ of heat energy had been emitted.

CO(g) + 2H2(g) CH3OH(l)CO volume, V (CO), equals 15 L or 0.015 m3.

Temperature = 85 0C = 85 + 273 = 358 K Pressure = 112 kPa = 112,000 PaPV = nRT n= 112000 0.015 / 8.314 358 n(CO) = 0.56 moles,

according to the ideal gas law.H2 volume is 14.4 L or 0.0144 m3

T = 750C + 273 K = 348 K n(H2) = 99191.84 0.0144 m3 / 8.314 348 K = 0.49 moles of H2 Pressure = 744 torr = 99191.84 Pa

Hydrogen is the limiting reagent, according to the calculation above.CH3OH = H2 = 0.49/2 = 0.245 m-238.6 (-110.5) = -128.1 kJ/mol for H(rxn) = H(f) (CH3OH) - H (rxn)

We must now multiply H(rxn) by the number of moles of methanol.

E = H(rxn) n(CH3OH) = 128.1 0.245 = 40.6 kJ.

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2 years ago
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