Help with number 20-22 please
1 answer:
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The answer for the following problem is described below.
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Explanation:
Given:
enthalpy of combustion of glucose(Δ of
) =-1275.0
enthalpy of combustion of oxygen(Δ of
) = zero
enthalpy of combustion of carbon dioxide(Δ of
) = -393.5
enthalpy of combustion of water(Δ of
) = -285.8
To solve :
standard enthalpy of combustion
We know;
Δ = ∈Δ
(products) - ∈Δ
(reactants)
(s) +6
(g) → 6
(g)+ 6
(l)
Δ = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]
Δ = [6 (-393.5) + 6(-285.8)] - [0 - 1275]
Δ = 6 (-393.5) + 6(-285.8) - 0 + 1275
Δ = -2361 - 1714 - 0 + 1275
Δ =-2800 kJ
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Answer:
The final state of the substance is a gas.
The sample is initially a liquid. One or more phase changes will occur.
Explanation:
Let's consider the phase diagram for Argon (not to scale).
<em>A sample of argon is initially at a pressure of 49.6 atm and a temperature of 101.4 K. The pressure on the sample is reduced to 0.680 atm at a constant temperature of 101.4 K. Which of the following are true? Choose all that apply </em>
<em>The final state of the substance is a gas.</em> TRUE. At 0.680 atm and 101.4 K, the substance is a gas.
<em>The gas initially present will solidify.</em> FALSE. Initially, Ar is present as a liquid.
<em>The final state of the substance is a solid.</em> FALSE.
<em>The sample is initially a liquid. One or more phase changes will occur.</em> TRUE. The sample is initially liquid and only one phase change will occur.
Solution :
Given :
The steady state flow = 8000
The concentration of the particulate matter = 18 mg/L
Therefore, the total quantity of a particulate matter in fluid
If 60 mg of alum required for one litre of the water treatment.
So Alum required for
or 480 kg/d
Therefore the alum required is 480 kg/d
1 mg of the alum gives 0.234 mg alum precipitation, so 60 mg of alum will give
mg of alum ppt. per litre
480 kg of alum will give = 480 x 0.234 kg/d
= 112.32 kg/d ppt of alum
Daily total solid load is
= 256.32 kg/d
So, the total concentration of the suspended solid after alum addition
= 32.04 mg/L
Therefore total alum requirement = 480 kg/d
b). Initial pH = 7.4
The dissociation reaction of aluminium hydroxide as follows :
After addition, the aluminium hydroxide pH of water will increase due to increase in ions.
Therefore, the pH of water will be acceptable range after the addition of aluminium hydroxide.
c). The reaction of and water as follows :
For the atmospheric pressure :
And the pH is reduced into the range of 5.9 to 6.4
Sun to kelp
kelp to sea urchin
sea urchin to otter
otter to shark
kelp,sea urchin,otter,shark to bacteria
bacteria back to kelp
