Answer:
a)52.58 m/s
b)56.13°
Explanation:
assume the upward direction as positive
x-component of the velocity = 29.3×cos33.6°=24.40 m/s (remain constant)
y-component of the velocity which is -29.3sin33.6°= -16.21 m/s
time of flight = 68.3/24.40= 2.7991 seconds
now, we can obtain final velocity in y-direction
![v_f_y= v_i_y-gt](https://tex.z-dn.net/?f=v_f_y%3D%20v_i_y-gt)
![v_f_y=-16.21-(-9.8)×2.7991](https://tex.z-dn.net/?f=v_f_y%3D-16.21-%28-9.8%29%C3%972.7991)
=43.66 m/s
![v_0=\sqrt{29.3^2+43.66^2}](https://tex.z-dn.net/?f=v_0%3D%5Csqrt%7B29.3%5E2%2B43.66%5E2%7D)
=52.58 m/s
for direction
![tan^{-1}\frac{43.66}{29.3}](https://tex.z-dn.net/?f=tan%5E%7B-1%7D%5Cfrac%7B43.66%7D%7B29.3%7D)
56.13° from the horizontal
Explanation:
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Answer:
Current flowing in the cell will be equal to 0.1284 mA
Explanation:
We have given charge q = 3.70 C
And time through which charge is flowing = 8 hour
We know that 1 hour = 60 minutes, and 1 minute = 60 sec
So 1 hour = 60×60 = 3600 sec
So 8 hour = 8×3600 = 28800 sec
We know that current is rate time rate of flow of charge
So current ![i=\frac{q}{t}=\frac{3.70}{28800}=1.284\times 10^{-4}A=0.1284mA](https://tex.z-dn.net/?f=i%3D%5Cfrac%7Bq%7D%7Bt%7D%3D%5Cfrac%7B3.70%7D%7B28800%7D%3D1.284%5Ctimes%2010%5E%7B-4%7DA%3D0.1284mA)
So current flowing in the cell will be equal to 0.1284 mA
The law of conservation of mass<span> states that </span>mass<span> in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the </span>law of conservation of mass<span>, the </span>mass<span> of the products in a chemical reaction must equal the </span>mass<span> of the reactants.
</span>
Every chemical equation<span> adheres to the </span>law of conservation of mass<span>, which states that </span>matter<span> cannot be created or destroyed. Therefore, there must be the same number of atoms of each element on each side of a chemical </span>equation.
Answer:
It reminds us that we need to work harder. It allows us to make adjustments in the way and manner in which we train and practice. In a loss, we are able to identify our vulnerabilities and weaknesses, and work to improve.
Explanation: