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S_A_V [24]
3 years ago
12

Reflecting the graph of y=cosx across the y axis is the same as not reflecting it at all.

Mathematics
2 answers:
weqwewe [10]3 years ago
5 0
Refrecting the graph of y = cos x across the y axis is the same as not refrecting it at all since y = cos x is an even function. i.e. cos x = cos (-x). Hence the statement is true.
Fittoniya [83]3 years ago
4 0

Answer:

True

Step-by-step explanation:

The graph of y=\cos(x) is an even function.

This means that the graph of y=\cos(x) is symmetric about the y-axis.


If we reflect the graph of y=\cos(x) about the y-axis, it will fall exactly on its outline.

This makes it behave as if it has not been reflected at all.


In other words, the mapping for reflection about the y-axis is

(x,y)\rightarrow(-x,y)


Since \cos(-x)=\cos(x)

The graph will retrace its outline.

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A right-angled triangle has sides which are 5 inches and 12 inches. How long is the triangle's hypotenuse?
Andrew [12]

Answer:

13 inches

Step-by-step explanation:

Use the Pythagorean Theorem:

a^2 + b^2 = c^2

(5)^2 + (12)^2 = c^2

c^2 = 169 in^2

c = 13 inches

4 0
2 years ago
1/7 + 6/7 equals1/7 + 6/7 equals
Ivanshal [37]

Answer:

7/7 = 1

Step-by-step explanation:

1/7 is one out of seven part plus 6/7 which is 6 out of seven parts. The denominator does not need to change because it is a common denominator. Just simply add the numerators, 1 and 6 and you get 7. The numerator is divided by the denominator (7/7) which equals to 1.

4 0
3 years ago
Read 2 more answers
Simplify this number 300mm:9m​
DIA [1.3K]

Answer:

1 : 30

Step-by-step explanation:

300mm:9m​

We need to change the meters to mm

1 meter is 1000 mm

so 9 m is 9000 mm

300mm:9000mm

Divide both sides by 300

​300mm/300 : 9000/300

1 : 30

5 0
3 years ago
A parabola opening up or down has vertex (0,0) and passes through (12, -18). Write its
denis-greek [22]
The equation is y= -1/8x^2
4 0
3 years ago
20 PTSS !!!<br> PLEASE HELPP !!
butalik [34]

Because it is extremely hard to find the area of this figure all together, it would be in our best interest to split this figure up into three different pieces: the two horizontal rectangles, and the verticle rectangle. We can find the area of all three and add them up. Be aware that there are two different ways that you can break this figure up, As shown in the attachments. I will be using the first image (the one with the tall horizontal rectangles, NOT the almost-squares).

So, we see that we have enough information to solve for the area of the left-most rectangle. Area = lw. 10 x 4 = 40, so the area is 40. Next, we have to notice, that the horizontal rectangles are also the same, so both of the areas of the two horizontal rectangles are 40.

Now, we can find the middle rectangle. We know that the length of the entire thing is 18, but it is taken up by 8 (4+4) of the horizontal triangles, so 18-8=10, so the length Is 10. We also know that the height of the horizontal rectangles is 10, so 10-3=7. Our dimensions for the rectangle are 10x7 or 70 square units. If we add them all together, 40+40+70=150.

The area is 150 square units

8 0
3 years ago
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