Answer: Option (a) is the correct answer.
Explanation:
A chemical formula which represents proportions between the elements present in a compound is known as empirical formula.
When chemical or molecular formula is able to be reduced to smaller whole-number ratio of the elements then both molecular and empirical formulas are considered to be the same.
Relation between molecular formula and empirical formula is as follows.
Molecular formula = n × Empirical formula
where, n is an integer.
Chemical formula of acetic acid is
.
Chemical formula of formaldehyde is
. It is the smaller whole-number ratio of molecular formula of acetic acid.
Chemical formula of Benzaldehyde is
.
Chemical formula of glucose is
.
Thus, we can conclude that formaldehyde molecules has/have the same empirical formula as acetic acid (
).
Combustion of any hrdrocarbon yields carbon dioxide and water such that the hydrogen and carbon are derived from the hydrocarbon.
1 mole of carbon dioxide has a mass out of which 12 g is the mass of carbon, therefore, 3.38 g of carbon will contain (3.38 × 12)/44 = 0.922 g of carbon.
Thus, since the hydrocarbon has a mass of 1 g, then the mass of hydrogen will be (1-0.922 g) = 0.078 g.
To get the empirical formula we divide the mass of each element by the atomic mass to get the number of moles.
Carbon= 0.922/12 = 0.0768 moles
Hydrogen = 0.078/1 = 0.078 moles
Then we get the ratio of the moles of carbon : hydrogen
= 0.0768 : 0.078
= 1 : 1.016
≈ 1: 1
Therefore the empirical formula of the hydrocarbon will be CH
Answer:
Sorry i really dont know goodluck
Explanation:
Answer:

Explanation:
Two important formulas in radioactive decay are

1. Calculate the decay constant k

2. Calculate the mass remaining

Answer:
Number of iodine atoms = 2 × 4 = 8
Number of oxygen atoms = 2 × 9 = 18
Explanation:
Coefficient 2 is placed in front of the product tetraiodine nonaoxide:
= 
Number of iodine atom in a single molecule tetraiodine nonaoxide = 4
Number of oxygen atoms in a single molecule tetraiodine nonaoxide = 9
Coefficient 2 is placed in front of the product tetraiodine nonaoxide:
= 
Number of iodine atoms = 2 × 4 = 8
Number of oxygen atoms = 2 × 9 = 18