Question

A large hamburger sandwich contains 628 kcal and 36 grams of fat. Approximately what percentage of the total energy is contributed by fat

Answer 1

The percentage of the total energy contributed by fat = 51.59% of fat

Calculation of total energy in fat

The quantity of fat in the hamburger = 36grams

But 1 gram of fat = 9 kcal( standard energy value per gram of fat).

That is , 9kcal = 1 gram

X kcal = 36 grams

cross multiply,

X kcal = 9 × 36

= 324kcal

To calculate the percentage of 324kcal of fat in 628 kcal,

$\% = \frac{324}{628} \times \frac{100}{1}$

$\% = \frac{32400}{628}$

% = 51.59% of fat

The percentage of the total energy contributed by fat = 51.59%

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