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zaharov [31]
2 years ago
9

A large hamburger sandwich contains 628 kcal and 36 grams of fat. Approximately what percentage of the total energy is contribut

ed by fat
Chemistry
1 answer:
Klio2033 [76]2 years ago
3 0

The percentage of the total energy contributed by fat = 51.59% of fat

<h3>Calculation of total energy in fat</h3>

The quantity of fat in the hamburger = 36grams

But 1 gram of fat = 9 kcal( standard energy value per gram of fat).

That is , 9kcal = 1 gram

X kcal = 36 grams

cross multiply,

X kcal = 9 × 36

= 324kcal

To calculate the percentage of 324kcal of fat in 628 kcal,

\% =  \frac{324}{628}  \times  \frac{100}{1}

\% =  \frac{32400}{628}

% = 51.59% of fat

The percentage of the total energy contributed by fat = 51.59%

Learn more about fats here:

brainly.com/question/1601509

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Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

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Now put all the given values in the above equation, we get:

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One mole of a substance is the ratio of mass of the substance by the molecular mass of the substance. Thus the mass of one mole of a substance is equal to the substance's molecular weight. Thus one mole of a substance is the atomic mass unit of a substance and since one mole is equivalent to the Avagadro number,we can conclude that one Avagadro number is one atomic mass unit of the substance.

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