1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rewona [7]
3 years ago
6

4. Assuming the reaction below is at equilibrium, which of the following changes will drive the reaction to the left? C(s) + O2(

g) + CO2(g) AH -393.5 kJ/mol 1. Increasing the temperature 2. Adding O2(g) 3. Removing C(s) a. I only b. 2 only c. 3 only d. 1 and 3 e. 2 and 3
Chemistry
2 answers:
gtnhenbr [62]3 years ago
7 0

Answer:

The answer is 1. Increasing the temperature.

Explanation:

When changes are applied to a system that is at equilibrium it will respond according to Le Chatelier´s Principle. This principle states that changes in temperature, volume, pressure or concentration will cause the system to react in a way that opposes the change, trying to achieve a new equilibrium state.

In 1. we need to take into account that this is an exothermic reaction (ΔH° is negative). Therefore, we could imagine heat as one of the products.

C(s) + O₂(g) ⇄ CO₂(g) + heat

If we increase the temperature, the system will react trying to reduce it. To do so, it has to consume heat, that is, shift towards the reactants (left).

In 2, if we add O₂(g), its concentration increases and the system will try to decrease it by shifting the reaction towards the products (right) and consuming the O₂(g).

In 3, solids do not form part of the equilibrium (they are not in the equilibrium constant) because their concentration doesn´t change much over time. Therefore, adding or removing solid C(s) makes no change.

All in all, only 1. (increasing the temperature) will drive the reaction to the left.

shepuryov [24]3 years ago
4 0

Answer:

Increasing temperature

Explanation:

C(s) + O_2(g) \leftrightharpoons CO_2(g)

Enthalpy of the reaction = -393.5 kJ/mol

Negative sign implies that reaction is exothermic.

Effect of change in reaction condition is explained by Le chateliers principle.

According to Le chateliers principle, if the reaction conditions of a reversible reaction in a state of dynamic equilibirum is changed, the reaction will move in a direction to counteract the change.

1. Increasing the temperature

Forward reaction is exothermic that means temperature increases in forward direction. Backward reaction will be endothermic and so there is decrease in temperature in backward direction or in left direction.

On increasing temperature, reaction will be move in direction to counteract the increased temperature, therefore reaction will move in left direction.

2. Adding O2

If O2 is added, then reaction will move in a direction in which its get consumed. So, reaction will move in forward direction or in right direction.

3. Removing C (s)

Le Chatelier's principle does not apply on solids, so removal of C(s) does not affect the equilibrium.

You might be interested in
)
xenn [34]

Answer:

Its C hope it helped

Explanation:

3 0
3 years ago
Consider two gases, A and B, are in a container at room temperature. What effect will the following changes have on the rate of
Tcecarenko [31]

Answer:

  1. decrease in temperature , decreases the kinetic movements of the gase molecules as a result decreases the frequency of collisions between gas molecules A and B consequently decreases the rate of reactions of gases A and B
6 0
2 years ago
You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

3 0
3 years ago
There are four substances, A, B C and D. A and C are pure substances. They cannot be broken down into anything simpler by chemic
yarga [219]

The answer is C Becuz D is a compound and that is the only answer that says it

6 0
3 years ago
Is xenon (xe) more or less reactive than bromine (br)? why? ​
galben [10]

Answer:

Xenon is less reactive.

Explanation:

Xenon is a noble gas with 8 valence electrons whereas bromine is a halogen with 7 and is very reactive.

7 0
3 years ago
Other questions:
  • 1cg is equal to what
    13·1 answer
  • What are the electrons for calcium
    15·1 answer
  • Which formula equation shows a reversible reaction?
    15·2 answers
  • The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution
    7·2 answers
  • The compound consists of 40% carbon and 6.71% hydrogen. Its mass of 1 liter of steam is 2.4 g. What is the formula of the compou
    11·1 answer
  • I need help . Pleaseee
    8·1 answer
  • 3. How many molecules are in 0.500 moles of sulfur?
    10·1 answer
  • What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol
    13·1 answer
  • What is a technique for gene therapy?
    10·1 answer
  • How much water must be added to 6.0 M silver nitrate in order to make 500 mL of 1.2 M solution?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!