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Hoochie [10]
3 years ago
14

Based on the information in the above chart, which of these bases would be the best conductor of electricity?

Chemistry
2 answers:
Furkat [3]3 years ago
5 0

Answer:

KOH

Explanation:

Sophie [7]3 years ago
3 0

Answer:

KOH

Explanation:

i did the usatestprep

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Calculate the empirical formula of each of the following substances with the following compositions.
OleMash [197]

Explanation:

Note: Molar masses of elements can be found online or in the periodic table.

Moles of Magnesium

= 3.60g / (24.3g/mol) = 0.148mol.

Moles of Chlorine

= 10.65g / (35.45g/mol) = 0.300mol.

Mole ratio of Magnesium to Chlorine

= 0.148mol : 0.300mol = 1 : 2.

Hence we have the empirical formula MgCl2.

Moles of Lithium

= 9.1g / (6.94g/mol) = 1.311mol.

Moles of Oxygen

= 10.4g / (16g/mol) = 0.650mol.

Moles ratio of Lithium to Oxygen

= 1.311mol : 0.650mol = 2 : 1.

Hence we have the empirical formula Li2O.

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3 years ago
Difine the term compound​
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Explanation:

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The asthenosphere is the part of the upper mantle just below the lithosphere that os involved in the plate tectonic movement anf
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3 0
3 years ago
How many moles of Chromium is in 4.41 ×10^24 atoms
zalisa [80]

7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.

<h3>How to find the number of moles ?</h3>

Number of moles = \frac{\text{Given number of atoms}}{\text{Avogadro's Number}}

     

<h3>What is Avogadro's Number ?</h3>

Avogadro's number is the number of particles in one mole of substance. 6.022 × 10²³ is known as Avogadro's Constant / Avogadro's Number.

Avogadro's Number = 6.022 × 10²³

Now put the values in above formula we get

Number of moles = \frac{\text{Given number of atoms}}{\text{Avogadro's Number}}

                             = \frac{4.41 \times 10^{24}}{6.022 \times 10^{23}}

                             = 7.32 moles

Thus from the above conclusion we can say that 7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.

Learn more about the Avogadro's Number here: brainly.com/question/1581342

#SPJ1

3 0
2 years ago
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