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3 years ago

7

Identify the hypothesis of the statement.

1 answer:

maw [93]3 years ago

5 0

That is about a 99% chance the kids will have red hair, sometimes they take different jeans from their aunts of uncles, maybe even grandparents.

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In the given figure pt is the bisector of angle qpr. qs=3x, rs=2x+2, pq=3y-1 and pr=y+5

Naddika [18.5K]

Answer:

See solutions below

Step-by-step explanation:

1) From the diagram QS = RS

3x = 2x+2

3x-2x = 2

x = 2

Since RS = 2x+2

RS = 2(2)+2

RS = 4 + 2

RS = 6

2) RQ = RS + QS

RQ = 2x+2 + 3x

RQ = 5x+2

RQ = 5(2)+2

RQ = 12

3) PQ = PR

3y-1 = y+5

3y-y = 5+1

2y = 6

y = 3

PQ = 3y-1

PQ = 3(3)-1

PQ = 8

4) PR = y+5

PR = 3+5

PR = 8

5) PQSR = PQ + QR

PQSR = 8 + 12

PQSR= 20

5 0

3 years ago

Hellllllllllpppppppppppppppppp Solve for t. −5t≥70

Zinaida [17]

Divide 70 by -5
and flip the sign when dividing by a negative number
70/-5= -14
t(less than or equal to)-14

7 0

3 years ago

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Y=3x+2 is the equation of a straight line graph. Where does it cross the y-axis?

tamaranim1 [39]

The line crosses the y-axis at point (0,2). You know this because the slope intercept form is y=mx+b. y is any point on the y-axis. m is the slope of the line. x is and point on the x-axis. Finally, b is the y-intercept or where the line crosses the y-axis. As a result, your equation has a 2 for b. So, your answer would be: the line crosses the y-axis at point (0,2). 2 being where the line crosses the y-axis.

8 0

3 years ago

Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving

faust18 [17]

Answer:

$Volume = \frac{384}{7}\pi$

Step-by-step explanation:

Given (Missing Information):

$y = x^\frac{3}{2}$ ; $y = 8$ ; $x=0$

Required

Determine the volume

Using Shell Method:

$V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy$

First solve for a and b.

$y = x^\frac{3}{2}$ and $y = 8$

Substitute 8 for y

$8 = x^\frac{3}{2}$

Take 2/3 root of both sides

$8^\frac{2}{3} = x^{\frac{3}{2}*\frac{2}{3}}$

$8^\frac{2}{3} = x$

$2^{3*\frac{2}{3}} = x$

$2^2 = x$

$4 =x$

$x = 4$

This implies that:

$a = 4$

For $x=0$

This implies that:

$b=0$

So, we have:

$V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy$

$V = 2\pi \int\limits^4_0 {p(y)h(y)} \, dy$

The volume of the solid becomes:

$V = 2\pi \int\limits^4_0 {x(8 - x^{\frac{3}{2}}}) \, dx$

Open bracket

$V = 2\pi \int\limits^4_0 {8x - x.x^{\frac{3}{2}}} \, dx$

$V = 2\pi \int\limits^4_0 {8x - x^{\frac{2+3}{2}}} \, dx$

$V = 2\pi \int\limits^4_0 {8x - x^{\frac{5}{2}}} \, dx$

Integrate

$V = 2\pi * [{\frac{8x^2}{2} - \frac{x^{1+\frac{5}{2}}}{1+\frac{5}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{x^{\frac{2+5}{2}}}{\frac{2+5}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{x^{\frac{7}{2}}}{\frac{7}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{2}{7}x^{\frac{7}{2}}]\vert^4_0$

Substitute 4 and 0 for x

$V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [{4*0^2 - \frac{2}{7}*0^{\frac{7}{2}}])$

$V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [0])$

$V = 2\pi * [{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}]$

$V = 2\pi * [{64 - \frac{2}{7}*2^2^{*\frac{7}{2}}]$

$V = 2\pi * [{64 - \frac{2}{7}*2^7]$

$V = 2\pi * [{64 - \frac{2}{7}*128]$

$V = 2\pi * [{64 - \frac{2*128}{7}]$

$V = 2\pi * [{64 - \frac{256}{7}]$

Take LCM

$V = 2\pi * [\frac{64*7-256}{7}]$

$V = 2\pi * [\frac{448-256}{7}]$

$V = 2\pi * [\frac{192}{7}]$

$V = [\frac{2\pi * 192}{7}]$

$V = \frac{\pi * 384}{7}$

$V = \frac{384}{7}\pi$

Hence, the required volume is:

$Volume = \frac{384}{7}\pi$

3 0

3 years ago

QUICK HELP HURRY MAKRIMG PIEPLE AS BRIANLDIT

ruslelena [56]

Answer:

36

Step-by-step explanation:

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3 years ago

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