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Reika [66]
2 years ago
12

A tank is 10 m long, 6 m wide, 3 m high, and contains kerosene with density 820 kg/m3 to a depth of 2.5 m. (Use 9.8 m/s2 for the

acceleration due to gravity.) (a) Find the hydrostatic pressure on the bottom of the tank. Pa (b) Find the hydrostatic force on the bottom of the tank. N (c) Find the hydrostatic force on one end of the tank. N
Physics
2 answers:
Valentin [98]2 years ago
7 0

Answer:

Explanation:

a )

Pressure on the bottom

= hdg

= 2.5 x 820 x 9.8

= 20090 N / m²

b )

force = area x pressure

= 20090 x 10 x 6 N

= 1205400 N

c )

Force on 10m x 2.5 m face

center of gravity of the tank will lie at height 2 .5 / 2 = 1.25 m

Pressure = hdg

= 1.25 x 820 x 9.8

= 10045 N/m²

force = pressure x area

= 10045  x 10 x 2.5

= 251125 N .

pashok25 [27]2 years ago
7 0

Answer:

Explanation:

length of tank, l = 10 m

width of tank, w = 6 m

height of tank, h = 3 m

density of kerosene, d = 820 kg/m³

g = 9.8 m/s²

(a) Hydrostatic pressure

P = h'  x d x g

P = 2.5 x 820 x 9.8 = 20090 Pa

(b) Force on bottom

F = Pressure x area of bottom

F = 20090 x 10 x 6

F = 1205400 N

(c) Force on arm 10 m x 2.5 m

The center of gravity of the tank = 2 .5 / 2 = 1.25 m

Pressure = hdg

P = 1.25 x 820 x 9.8

P = 10045 N/m²

Force = pressure x area

F = 10045  x 10 x 2.5

F = 251125 N

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The following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality

To answer the question, we have to know what mathematical operations are.

<h3>What are Mathematical operations?</h3>

Mathematical operations are operations which are performed to change the value of a variable. The arithmetic mathematical operations we have are

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Now, for two quantities with different unit dimensions, addition, subtraction and equality are not allowed because these mathematical operations require the quantities to be in the same unit dimensions

Also, for two different quantities with differnt unit dimensions, multiplication and division are allowed because these mathematical operations do not require the quantities to be in the same unit dimensions.

So, the mathematical operations that are allowed are multiplication and division while the mathematical operations that are not allowed are addition, subtraction and equality.

So, the following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality

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2 years ago
A helicopter starting on the ground is rising directly into the air at a rate of 25 ft/s. You are running on the ground starting
rusak2 [61]

Answer:

The rate of change of the distance between the helicopter and yourself (in ft/s) after 5 s is \sqrt{725} ft/ sec

Explanation:

Given:

h(t) =  25 ft/sec

x(t) = 10 ft/ sec

h(5) = 25 ft/sec . 5 = 125 ft

x(5) = 10 ft/sec . 5 = 50 ft

Now we can calculate the distance between the person and the helicopter by using the Pythagorean theorem

D(t) = \sqrt{h^2 + x^2}

Lets find the derivative of distance with respect to time

\frac{dD}{dt} (t)  = \frac{2h \cdot \frac{dh}{dt} +2x \cdot\frac{dx}{dt}} {2\sqrt{h^2 + x^2}}

Substituting the values of h(t) and  x(t) and simplifying we get,

\frac{dD}{dt}(t) = \frac{50t \cdot \frac{dh}{dt} + 20 \cdot \frac{dx}dt}{2\sqrt{625\cdot t^2 + 100 \cdot t^2}}

\frac{dh}{dt} = 25ft/sec

\frac{dx}{dt} = 10 ft/sec

\frac{Dd}{dt} (t) = \frac{1250t +200t}{2\sqrt{725}t}  = \frac{725}{\sqrt{725}}  = \sqrt{725} ft / sec

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2 years ago
Find the velociity of a car which travels 35 m to the right over a period of 40 seconds
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3 years ago
How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.​
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Answer:

4.2s

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Unknown:

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Power is the rate at which work is done;

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        Power  = \frac{work done}{time}  

   Time  = \frac{work done}{power}  

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<h3 />

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So, the kinetic energy Kair did the air molecules gain from the falling coffee filter is 0.0437 J

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