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raketka [301]
3 years ago
11

PLEASE HELPP!!! I NEED ANSWERS!!!

Physics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

0.5kg

Explanation:

Using formula f=ma,

6N=mx12m/s^2

6N/(12m/s^2)=m

0.5kg=m

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Explain how you can improve the accuracy of a measurement. <br>​
yKpoI14uk [10]
You use more significant figures. 5 sigfigs (1.0985) is more accurate than 2 sigfigs (1.0)
8 0
2 years ago
Read 2 more answers
Starting at (0,0) an object travels 36 meters north and then it covers 20 meters east. What is
Svetradugi [14.3K]

Answer:

Explanation:

Using the pythagoras theorem, the displacement is expressed as;

d² = x²+y²

y = 36m (north)

x = 20m east

Substitute;

d² = 36²+20²

d² = 1296+400

d² = 1696

d = √1696

d = 41.18m

For the direction;

theta = tan^-1(y/x)

theta = tan^-1(36/20)

theta = tan^-1(1.8)

theta = 60.95°

Hence the magnitude is 41.18m and the direction is 60.95°

8 0
3 years ago
A roller coaster travels around a vertical 8-m radius loop. Determine the speed at the top of the loop if the normal force exert
strojnjashka [21]

Answer:

v=10m/sec

Explanation:

From the question we are told that

Radius of vertical r= 8m

Force exerted by passengers is 1/4 of weight

Generally the net force acting on top of the roller coaster is give to be

F_N+Fg

where

F_N =forceof the normal

Fg= force due to gravity

Generally the net force is given to be FC(force towards center)

F_C =F_N + Fg

F_N =F_C -Fg

F_N=F_C-F_g

F_N=\frac{mv^2}{R} -mg

Mathematical we can now derive V

m_g + \frac{8m}{4}= \frac{mv^2}{8}

\frac{5mg}{4} =\frac{mv^2}{8}

v^2 =\frac{40*10}{4}

v=10m/sec

Therefore the speed of the roller coaster is given ton be v=10m/sec

5 0
3 years ago
D.) How can you demonstrate the magnetic force? Write with an example
Lena [83]

Explanation:

d) Magnetic force is the power that pulls materials together (magnet e. g iron)

an example :how magnet can pick up a coin.

e) frictional force produces when two surfaces are in contact with each other.

effects of friction : I) it produces heat

II) it causes loss in power.

4 0
3 years ago
When operated on a household 110.0 V line, typical hair dryers draw about 1450 W of power. The current can be modeled as a long,
dezoksy [38]

Answer:

0.075A

Explanation:

We can consider this system as a circuit, hence we can take the current from the formula for the electric power as follow

P=IV\\I=\frac{P}{V}=\frac{110V}{1450W}=0.075A

I hope this is useful for you

regards

4 0
3 years ago
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