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raketka [301]
3 years ago
11

PLEASE HELPP!!! I NEED ANSWERS!!!

Physics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

0.5kg

Explanation:

Using formula f=ma,

6N=mx12m/s^2

6N/(12m/s^2)=m

0.5kg=m

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When is the kinetic energy of the ball zero and when is it at its highest? When is its potential energy at its lowest and at its
liubo4ka [24]

Answer:

if there is only one planet in the universe and the ball is there it will have 0 kinetic energy if the ball is in the very center of that planet only if the planet itself is absolutely motionless. its at its highest if the planet is moving away from the ball at a slightly faster speed forever. Between point A and B both potential energy and kinetic energy are at perfect 0.

Explanation:

never will have a measurable kinetic or potential energy status unless every single object is included in the calculation.

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3 years ago
A photoelectric effect experiment finds a stopping potential of 1.93 V when light of wavelength 200 nm is used to illuminate the
GenaCL600 [577]

a) Zinc (work function: 4.3 eV)

The equation for the photoelectric effect is:

E=\phi + K (1)

where

E=\frac{hc}{\lambda} is the energy of the incident photon, with

h = Planck constant

c = speed of light

\lambda = wavelength

\phi = work function of the metal

K = maximum kinetic energy of the photoelectrons emitted

The stopping potential (V) is the potential needed to stop the photoelectrons with maximum kinetic energy: so, the corresponding electric potential energy must be equal to the maximum kinetic energy,

eV=K

So we can rewrite (1) as

E=\phi + eV

where we have:

\lambda=200 nm = 2\cdot 10^{-7} m

V = 1.93 V

e is the electron charge

First of all, let's find the energy of the incident photon:

E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2\cdot 10^{-7}m}=9.95\cdot 10^{-19} J

Converting into electronvolts,

E=\frac{9.95\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=6.22 eV

And now we can solve eq.(1) to find the work function of the metal:

\phi = E-eV=6.22 eV-1.93 eV=4.29 eV

so, the metal is most likely zinc, which has a work function of 4.3 eV.

b) The stopping potential is still 1.93 V

Explanation:

The intensity of the incident light is proportional to the number of photons hitting the surface of the metal. However, the energy of the photons depends only on their frequency, so it does not depend on the intensity of the light. This means that the term E in eq.(1) does not change.

Moreover, the work function of the metal is also constant, since it depends only on the properties of the material: so \phi is also constant in the equation. As a result, the term (eV) must also be constant, and therefore V, the stopping potential, is constant as well.

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The impulse of a constant force is equal to
Nookie1986 [14]

Answer:

Explanation:

It's equal to change of momentum in contact

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Altitude is the angle measured above ____.<br><br> North Pole<br> horizon<br> equator<br> zenith
juin [17]
Altitude is the angle measured above the horizon
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How many joules are required to heat .250 kg of liquid water from 0 °C to 100 °C ?
dedylja [7]

Answer:

Specific heat of water is 4.186 J/g/C. The heat required to raise the temperature by

is

Here  is mass of water being heated,  specific heat of water and  change in temperature.

Here .

Heat energy required is

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