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const2013 [10]
3 years ago
14

what would the percentage of thorium-232 ( parent compound) be in a rock that was dated at 1.8 billion years

Chemistry
1 answer:
vovikov84 [41]3 years ago
7 0

The half-life of Th-232 is 1.405 × 10¹⁰ years  

Time elapsed = 2.8 x 10⁹ years  

Equation of radioactive decay:

A = A₀ = (1/2)^ t/t₁/₂

Thus, the percentage of thorium-232 in the rock that was dated at 2.8 billions year = 87.1%

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5.40X10^2kj converted into j
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Answer:

540,000 (5.4X10^5)

Explanation:

kj means Kilojoules, while we are converting to joules.

- Kilo, or k, represents our base value, Joules, multiplied by 10^3. To convert to joules, we would simply multiply by 10^3 (which is 1000)

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2 years ago
A gaseous compound has a mass of 8.00 g at 2.81 atm and 300. K in a 1.00 L container.
Maurinko [17]

Answer:

The question asks for moles, which can be obtained from P-V-T data using the ideal gas

equation: n =

RT

PV .

Now use the rearranged gas law to determine the number of moles in the sample:

!

n = PV

RT = (6.47 x 105 Pa)(5.65 x 10-4m3

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(8.314 J

mol K )(21.7 + 273.15 K) = 0.149 mol.

All conditions except the pressure and volume are fixed, so P1V1 = P2V2 can be used: 3.62 L

101kPa

(647 kPa)(0.565 L)

2

1 1

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PV V

Explanation:

4 0
3 years ago
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T/F according to the law of conservation of energy, when you use energy
Bond [772]
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5 0
3 years ago
What reaction conditions most effectively conver a cabocxylic acid to a methly ester?
VLD [36.1K]

Answer:

Esterification reaction

Explanation:

When we have to go from an acid to an ester we can use the <u>esterification reaction</u>. On this reaction, an alcohol reacts with a carboxylic acid on acid medium to produce an ester and water. (See figure).  

In this case, we need the <u>methyl ester</u>, therefore we have to choose the <u>appropriate alcohol</u>, so we have to use the <u>methanol</u> as reactive if we have to produce the methyl ester.

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The Ostwald process for the commercial production of nitric acid from ammonia and oxygen involves the following steps:
bagirrra123 [75]

Answer:

12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow  14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)

Explanation:

The steps of the Ostwald process:

4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)

2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g)

3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g)

Combinning the equations:

4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)

+

(2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g))*2

+

(3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g))*4/3

=

4 NH_3 (g)+ 4 NO (g)+ 7 O_2 (g) + 4 NO_2 (g) +4/3 H_2O (l) \longrightarrow 4 NO (g) + 6 H_2O (g) +  4 NO_2(g) + 8/3 HNO_3 (g) + 4/3 NO (g)

Simplifying:

4 NH_3 (g)+ 7 O_2 (g) + \longrightarrow  14/3 H_2O (l) + 8/3 HNO_3 (g) + 4/3 NO (g)

12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow  14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)

The overall reaction is endothermic becuase the formation of new chemical bonds requires energy consumption.

4 0
3 years ago
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