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Andrei [34K]
3 years ago
11

If grade 7 students learn six periods and if one period is 40 minutes then how many seconds they learn per day

Physics
2 answers:
Ludmilka [50]3 years ago
6 0

Answer:

C. 14400

Explanation:

40min × 6 periods = 240mins total.

1 minute = 60 seconds.

240 minutes × 60 = 14400 seconds.

AURORKA [14]3 years ago
4 0
The answer is C.14400
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An opera singer sings a note that breaks a glass. This is an example of _____. consonance dissonance resonance reflection
IrinaVladis [17]
Resonance, Because its another way of saying sound waves. It determined the objects frequency. 
3 0
3 years ago
In the figure below, a block of 1.67 slides on a track with different levels, which has friction only at the highest point where
Natasha_Volkova [10]

Answer:

2.0 m

Explanation:

Energy is conserved.

Initial KE = Final PE + Work done by friction

½ mv² = mgh + Fd

½ mv² = mgh + mgμd

½ v² = gh + gμd

½ v² − gh = gμd

d = (½ v² − gh) / (gμ)

d = (½ (7.5 m/s)² − (10 m/s²) (2.1 m)) / ((10 m/s²) (0.35))

d = 2.0 m

7 0
3 years ago
A car is moving at a constant 34 m/s for 7 seconds. What is the average acceleration of the car?
Marina86 [1]
Since the body is moving with uniform motion therefore the body doesn't accelerate
therefore acceleration is 0m/s^2
7 0
3 years ago
If we double only the amplitude of a vibrating ideal mass-and-spring system, the mechanical energy of the system:
Lelechka [254]

Answer:

D. increases by a factor of 4.

Explanation:

General equation of SHM

Lets taken the general equation of the displacement given as

x = A sinω t

A=Amplitude ,t=time ,ω=natural frequency

We know that speed V

V=\dfrac{dx}{dt}

V= A ω cosωt

The mechanical energy of spring mass system

U=\dfrac{1}{2}KA^2

K=Spring constant

Now when Amplitude A become 2 times then the mechanical energy will become 4 times.

Therefore the answer is D.

8 0
3 years ago
Sam threw a stone horizontally at a speed of 5m/s from a 9.8 m tall building. how much time does the stone take to hit the groun
taurus [48]
The given is a projectile motion with angle equal to 90° at which the motion would become horizontal. The projectile motion has two components for the distance. The horizontal component would progress at a constant rate each second while the vertical component would become greater as time progress. 

In this item, we are asked to determine the amount of time that would be needed for the stone to hit the ground. This can be calculated through the equation,
            
           d = V₀t + (1/2)(gt²)
It is to be noted that V₀ has a y-component equal to zero. 

Substituting this value to the equation,
          9.8 m = (0) + (1/2)(9.8 m/s²)(t²)
                  t = sqrt (2) = 1.41 s

Hence, the time would be equal to 1.41 s. 
7 0
3 years ago
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