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Keith_Richards [23]
9 months ago
10

16) Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radi

us of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2) A) 19.5 km/s B) 27.5 km/s *C) 11.2 km/s D) 20.5 km/. orbital speed?
​
Physics
1 answer:
ArbitrLikvidat [17]9 months ago
4 0

The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C

<h3>What does Orbital speed depend on ?</h3>

The speed of an object travelling around a circle depends on two quantities namely;

  • Its angular velocity w
  • Its distance from the center of the circle.

Given that  an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)

The given parameters are:

  • The mass of Saturn = 5.68 x 10^26 kg
  • The orbital radius = 3.00 x 105 km
  • G = 6.67 × 10-11 N·m2/kg2

Let us first calculate the gravitational field strength on the Saturn.

g = GM/r²

Substitute all the necessary parameters and convert km to m

g = (6.67 × 10^{-11} × 5.68 × 10^{26}) ÷ (300000 × 1000)²

g = 3.79 × 10^{16} ÷ 9 × 10^{16}

g = 0.421 m/s²

The  orbital speed will be

V² = gr

V² = 0.4211 × 300000 × 1000

V² = 126333333.3

V = √126333333.3

V = 11239.8 m/s

Convert it to Km/s by dividing the answer by 1000

V = 11239.8/1000

V = 11.2 Km/s

Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s

Learn more about Orbital Speed here: brainly.com/question/22247460

#SPJ1

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Answer:

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Explanation:

If we assume the gas is a perfect gas we can use the perfect gas equation:

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Where subscripts 1 shows before the isothermal process and 2 after it, because isothermal means constant temperature T1=T2, and pressure increases by 10% means P2=1,1*P1, using these facts on (1) we have:

V_{2}=\frac{V_{1}}{1.1} (2)

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\frac{P_{2}V_{2}}{T_{2}}=\frac{P_{3}V_{3}}{T_{3}} (3)

Where subscripts 2 shows before the isobaric process and 3 after it, because isobaric means constant pressure P2=P3, and volume decreases by 20% means V3=0.8*V2, using these facts on (3) we have:

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Where subscripts 3 shows before the isochoric process and 4 after it, because isochoric means constant volume V3=V4, and temperature increases by 15% means T4=1.15*T3, using these facts on (5) we have:

P_{4}=1.15P_{3} (6)

So now because P4=1.15*P3, P2=P3 and P2=1.1*P1:

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This is, the new pressure of the gas increases by 26.5%  with respect to initial pressure.

Similarly, we have V3=V4, V3=0.8*V2 and V1=1,1*V2:

V_{4}=\frac{0.8}{1.1}V_{1}=0.72V1

so the final volume decreases 27% with respect to initial volume.

T4=1,15*T3, T3=0.8*T2 and T1=T2:

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A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to
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Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

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Answer:

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