Energy=mass*SHC*temp change
=100*0.9*75
=6750J
Acceleration=Final velocity-Initial velocity /time.
Acceleration=a=4m/s².
Initial velocity= u= 44m/s
Final velocity=v= let it be v, since we are to look for the final velocity.
Time=t=10seconds.
Mathematically:
a=v-u/t
Substituting the givens into the equation.
4=v-44/10
cross multiply.
4×10 = v-44
40=v-44
40+44=v
v=84m/s
Answer:
Efficiency of machine=4.9
Explanation:
We are given that
Mass of load=100 kg
Effort=20 N
Velocity ratio=10
We have to find the efficiency of machine.
Load=
Efficiency=
Using the formula
Efficiency of machine=
Efficiency of machine=
Efficiency of machine=4.9
Answer: A transformer that increases the voltage from primary to secondary (more secondary winding turns than primary winding turns) is called a step-up transformer. As a step-down unit, this transformer converts high-voltage, low-current power into low-voltage, high-current power.
Explanation:
