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melamori03 [73]
3 years ago
15

What is the mass of an object that is 6kg on a planet with an acceleration due to gravity

Physics
1 answer:
goldfiish [28.3K]3 years ago
6 0

Answer:

Mass of the body will be = 6 kg

Explanation:

Given:

Mass of an object = 6 kg

Acceleration due to gravity of the planet = 10 m/s^2

To find the mass of the body on that planet.

Solution:

Mass of the body is defined as the total amount of matter contained in the body.

Thus, mass of a body will always remain constant irrespective of the acceleration due to gravity. This is because it is an independent quantity and does not vary with acceleration due to gravity.

<em>It is the weight of the body that changes with the change in the acceleration due to gravity as it is given by:</em>

W=mg

where m represents mass of the body and g represents the accelration due to gravity.

Hence, the mass of the given body will remain = 6 kg.

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The electric output of a power plant is 716 MW. Cooling water is the main way heat from the powerplant is rejected, and it flows
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Answer:

(a) 83475 MW

(b) 85.8 %

Explanation:

Output power = 716 MW = 716 x 10^6 W

Amount of water flows, V = 1.35 x 10^8 L = 1.35 x 10^8 x 10^-3 m^3

mass of water, m = Volume  x density = 1.35 x 10^8 x 10^-3 x 1000

                                                               = 1.35 x 10^8 kg

Time, t = 1 hr = 3600 second

T1 = 25.4° C, T2 = 30.7° C

Specific heat of water, c = 4200 J/kg°C

(a) Total energy, Q = m x c x ΔT

Q = 1.35 x 10^8 x 4200 x (30.7 - 25.4) = 3 x 10^12 J

Power = Energy / time

Power input = P = \frac{3 \times 10^{12}}{3600}=8.35 \times 10^{8}W

Power input = 83475 MW

(b) The efficiency of the plant is defined as the ratio of output power to the input power.

\eta =\frac{Power output}{Power input}

\eta =\frac{716}{83475}=0.858

Thus, the efficiency is 85.8 %.

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