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Anit [1.1K]
3 years ago
10

A characteristic in an experiment, such as how much food, how much space, how hot or how cold, is termed a ____________. (spelli

ng counts, so be careful!)
Physics
2 answers:
KATRIN_1 [288]3 years ago
6 0
I think the term is a variable?
yuradex [85]3 years ago
3 0
Variables are what we change in an experiment to test their effects on whatever it is we are measuring. Hope that helps!
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How much force should a mother exert to lift a 5.0-kg child​
andrew11 [14]

Answer:

F = 49N

Explanation:

F = mg

F = 5kg × 9.8m/s^2

F = 49kg.m/s^2 = 49N

8 0
3 years ago
Temperatures of gases inside the combustion chamber of a four‑stroke automobile engine can reach up to 1000°C. To remove this en
Alona [7]

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thats a lot, which one u want me to do?

Explanation:

8 0
3 years ago
The engine oil at 150 degree Celsius is cooled to 80 degree Celsius in a parallel flow heat exchanger by water entering at 25 de
Setler [38]

Answer:

Explanation:

Attach is the solution

6 0
3 years ago
Earlier we discussed the concept of isostasy, where lower density rocks rise higher than higher density rocks. How is the variat
Elena L [17]

The variation of water depth at spreading centers (ridges) controlled by isostasy  as convective cooling cools the rocks much more effectively the than heat conduction.

<h3>What is convective heat transfer?</h3>

When heat transfer takes place between the two fluids in direct or indirect contact.

The lithosphere cools when it moves away from the ridge axis by sea floor spreading. The cooler rocks have low density, so the sea floor gets deeper as the lithosphere gets more dense.

Thus, the convective cooling cools the rocks much more effectively the than heat conduction.

Learn more about convective heat transfer

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4 0
2 years ago
a u tube contains a liquid of an unknown density an oil of density is poured into the right arm of the tube until the oil column
scoray [572]

Answer:

The answer is "1155\ \frac{kg}{m^3}"

Explanation:

Please find the complete question in the attached file.

p = p_0 + ?gh

pi = pressure only at two liquids' devices

PA = pressure atmosphere.

1 = oil density

2 = uncertain fluid density

h_1 = 11 \ cm\\\\h_2= 3 \ cm

The pressures would be proportional to the quantity 11-3 = 8 cm from below the surface at the interface between both the oil and the liquid.

\to p_A + ?2g(h_1 - h_2) = p_A + ? 1gh_1\\\\\to ?2 = \frac{?1h_1}{(h_1 - h_2)} \\\\

       = \frac{840 \frac{kg}{m^3}}{\frac{11}{8}} \\\\= 1155\ \frac{kg}{m^3}

8 0
3 years ago
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