Ask question

Ask question

All categories

3 years ago

10

A characteristic in an experiment, such as how much food, how much space, how hot or how cold, is termed a ____________. (spelli

ng counts, so be careful!)

2 answers:

KATRIN_1 [288]3 years ago

6 0

I think the term is a variable?

yuradex [85]3 years ago

3 0

Variables are what we change in an experiment to test their effects on whatever it is we are measuring. Hope that helps!

You might be interested in

Help me, what is the shape of solid?

Naily [24]

Explanation:

Solids have a definite shape and definite volume.

3 0

2 years ago

Read 2 more answers

What is the universe made of? Astronomers face an embarrassing conundrum: they don't know what 95% of the universe is made of

rewona [7]

Answer:

This what they all been waiting for

I guess so

They been waiting for this sh,it for a long time didn't they

I'ma give it everything I got

Ayo Dougie park that X6 around the corner

Aye I'm just feeling my vibe right now

I'm feeling myself

Explanation:

3 0

3 years ago

Identify which type of source is being described.

frez [133]

Answer:

Primary, secondary

Explanation:

3 0

3 years ago

Read 2 more answers

Please help me I have to send for my teacher

expeople1 [14]

Answer:

for the fill in the blanks

1- static

2-kinetic

3-coeffiecient

4-opposite to

5-sin theta

6-cos theta

im not sure however what to do with the top part or if its even part of what you need help with

8 0

2 years ago

A shell is fired at an angle of 35° above the horizontal at a velocity of 40 m/s. (a) What is it's speed at the highest point of

Fudgin [204]

Answer:

Part a)

$v_f = v_x = 32.77 m/s$

Part b)

T = 4.68 s

Explanation:

Part a)

Shell is fired at speed of 40 m/s at angle of 35 degree

so here we have

$v_x = 40 cos35 = 32.77 m/s$

$v_y = 40 sin35 = 22.94 m/s$

since gravity act opposite to vertical speed of the shell so at the highest point of its trajectory the vertical component of the speed will become zero

so at the highest point the speed is given

$v_f = 32.77 m/s$

Part b)

After completing the motion we know that the displacement of the object will be zero in Y direction

so we have

$\Delta y = 0$

$0 = v_y t - \frac{1}{2}gt^2$

$T = \frac{2v_y}{g}$

$T = \frac{2(22.94)}{9.81} = 4.68 s$

7 0

3 years ago