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Neko [114]
3 years ago
14

No nuclear reactions occur in the interior of a white dwarf. its brilliance comes from stored heat. therefore, the fate of an is

olated white dwarf is to slowly lose its stored energy and dim over a long period of time. however, if a white dwarf is a member of a binary-star system with specific properties, the white dwarf can become explosively active. label the components of such a binary-star system capable of producing a nova event.
Physics
1 answer:
Snowcat [4.5K]3 years ago
3 0
For a white dwarf star<span> to become explosively active, </span>the gap<span> between the dwarf </span>and therefore the<span> companion </span>should<span> be </span>sufficiently little<span> that the white dwarf's </span>force field will<span> pull matter </span>aloof from<span> the surface of the companion. </span>because of<span> the rotation of the </span>positional representation system<span>, the matter flowing through the mass-transfer stream from the companion star forms a </span>flat <span>disk, </span>known as associate degree<span> accretion disk, </span>that<span> orbits </span>round the white dwarf star<span>.</span>
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I will pick the branliest if answered these questions.
Bond [772]

1.

n₁ = index of refraction of diamond = 2.4

n₂ = index of refraction of water = 1.33

θ₁ = angle of incidence = 24 deg

θ₂ = angle of refraction = ?

using snell's law

n₁ Sinθ₁ = n₂ Sinθ₂

inserting the values

(2.4) Sin24 = (1.33) Sinθ₂

θ₂ = 47.22 deg


2.

c = specific heat = 4.18

m = mass of water = 3.5 kg

ΔT = change in temperature = 55 - 25 = 30 C

Q = heat taken

heat taken is given as

Q = m c ΔT

inserting the values

Q = (3.5) (4.18) (30)

Q = 439 J


3.

n = number of moles = 1

m = molar mass = 0.0399 kg

T = temperature = 27 K

v = average velocity

average velocity is given as

v = sqrt(3RT/m)

v = sqrt(3 x 8.314 x 275/0.0399)

v = 414.6m/s


4.

n = number of moles = 2

T = temperature = 35 C  = 35 + 273 K = 308 K

U = internal energy

internal energy is given as

U = 2.5 n RT

U = 2.5 (2) (8.314) (308

U = 1.28 × 10⁴ J


5.

F₁ = 3300 N

F₂ = ?

A₁ = 0.060 m²

A₂ = 0.18 m²

Using pascal's law

F₁/A₁ = F₂/A₂

3300/0.060 = F₂/0.18

F₂ = 9900 N


6.

R = resistance of each resistance in series = 10 ohm

R' = equivalent resistance in series

equivalent resistance is given as

R' = 3 R

R' = 3 x 10

R' = 30 ohm


7.

R = resistance of each resistance in parallel = 10 ohm

R'' = equivalent resistance in parallel

equivalent resistance is given as

R'' = R/3

R'' = 10/3

R'' = 3.3 ohm


8.

for series circuit

R' = equivalent resistance in series = 30 ohm

V = Voltage applied = 60 Volts

i' = current in each resistor in series

current in each resistor in series is given as

I' = V/R'

i' = 60/30

i' = 2 A


for parallel circuit :

i = current in each resistor = V/R = 60/10 = 6 A








6 0
4 years ago
Read 2 more answers
what will be the gravitational force between two bodies if the mass of each is doubled and the distance between them is halved?
katen-ka-za [31]

Answer:

Gravitational force will be 16 times more.

Explanation:

we know;

Gravitational force (F) = (Gm1m2)/d^2

when mass of each is doubled and distance between them is halved;

F= (G2m1×2m2)/(d/2)^2

=(4Gm1m2)/(d^2/4)

=4×4(Gm1m2)/d^2

=16(Gm1m2)/d^2

=16F

3 0
3 years ago
Energy may be measured in?​
hram777 [196]

Answer:

Energy May be measured in joule

6 0
3 years ago
Explain the process of <br>anomalous expansion of water​
Kay [80]

The anomalous expansion of water refers to the fact that water, unlike most substances, expands when it freezes. The density of water increases as temperature decreases but reaches a maximum at 4° C then begins to expand.

When liquid water is cooled, it contracts like one would expect until a temperature of approximately 4 degrees Celsius is reached. After that, it expands slightly until it reaches the freezing point, and then when it freezes it expands by approximately 9%.

8 0
3 years ago
A book light has a 1.4 W, 4.8 V bulb that is powered by a transformer connected to a 120 V electric outlet. The secondary coil o
VLD [36.1K]

Answer:

Turns of the primary coil: 500

Current in the primary coil: Ip= 0.01168A

Explanation:

Considering an ideal transformer I can propose the following equations:

        Vp×Ip=Vs×Is

Vp= primary voltaje

Ip= primary current

Vs= secondary voltaje

Is= secondary current

        Np×Vs=Ns×Vp

Np= turns of primary coil

Ns= turns of secondary coil

From these equations I can clear the number of turns of the primary coil:

Np= (Ns×Vp)/Vp = (20×120V)/4.8V = 500 turns

To determine the current in the secondary coil I use the following equation:

Is= (1.4W)/4.8V = 0.292A

Therefore I can determine the current in the primary coil with the following equation:

Ip= (Vs×Is)/Vp = (4.8V×0.292A)/120V = 0.01168A

5 0
3 years ago
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