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Hitman42 [59]
2 years ago
12

Câu 1. Trường hợp nào dưới đây không phải là vật sáng?

Physics
1 answer:
Marianna [84]2 years ago
5 0

Answer:

A

Explanation:

A. The pencil is on the table in broad daylight

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Why is water considered to be a complex compound
DedPeter [7]
HEY THERE !!

\huge{COMPOUND:-}
Compounds contain two or more different elements. 


Water is a molecule because it contains molecular bonds . Water is also a compound  because it is made from more than one kind of element. (oxygen and hydrogen).

So If you like, you can say that water is a molecular compound.

HOPE IT HELPED YOU.
7 0
3 years ago
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Four students made a graphic organizer describing the parts of the atom.
Nikitich [7]

Answer:

I believe the answer is D.

Explanation:

Protons are found inside the nucleus so are neutrons. Electrons are found outside the nucleus.

8 0
3 years ago
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In the park, there are 25 pigeons, 15 squirrels, 5 rabbits, and 5 stray cats. Why
Debora [2.8K]

Answer: Line graph should be used to show how one variable changes over time not to show multiple categories or variables are at one specific point in time.

Explanation:

In maths, statistics, and related fields, graphs are used to visually display variables and their values. In the case of line graphs, these are mainly used to display evolution or change of a variable over time. For example, a line graph can show how the number of divorces changed from 1920 to 2010.

In this context, the number of different animals in the park cannot be represented through a line graph because this situation does not imply a variable changing over time. Moreover, this situation includes multiple variables or categories of animals and the data shows only one specific point in time, which can be better represented through a bar graph.

8 0
3 years ago
You buy a 75 watt light bulb. the label means that
alukav5142 [94]
The label means that the bulb will consume 75 joules of electrical energy in 1 sec
4 0
3 years ago
Suppose you wish to fabricate a uniform wire out of 1.10 g of copper. If the wire is to have a resistance R = 0.390 Ω, and if al
Citrus2011 [14]

To solve this problem we will apply the concepts related to volume, as a function of length and area, as of mass and density. Later we will take the same concept of resistance and resistivity, equal to the length per unit area. Once obtained from the known constants it will be possible to obtain the area by matching the two equations:

Mass of copper wire(m) = 1.10g = 1.10*10^{-3} kg

Density (\rho)= 8.92*10^3kg/m^3

Resistively of copper (\gamma) = 1.7*10^{-8}\Omega \cdot m

Resistance (R) = 0.390\Omega

Volume is defined as,

V= lA \text{ and }\frac{m}{\rho}

lA= \frac{1.10*10^{-3}}{8.92*10^3}

lA = 1.233*10^{-7} m^3 (1)

We know that,

\frac{l}{A} = \frac{R}{\gamma}

\frac{l}{A}= \frac{0.390\Omega}{1.7*10^{-8}\Omega m}

\frac{l}{A} = 2.2941*10^7 m^{-1} (2)

Multiplying equation we have

l^2 = (1.233*10^{-7})( 2.2941*10^7)

l^2 = 2.8286m^2

l =\sqrt{2.8286m^2}

l = 1.68m

Therefore the length of the wire is 1.68m

6 0
3 years ago
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