Answer:
v = √(2gh)
Assuming g = 9.81m/s^2
v = √(19.62h)
Explanation:
Let v represent the speed of the ball just before it collide with the ground.
Applying the equation of motion;
v^2 = u^2 + 2as
Where;
v = final velocity
u = initial speed = 0 (starting from rest)
a = acceleration= g acceleration due to gravity
s = distance covered = h
So, substituting the values;
v^2 = 0^2 + 2gh
v^2 = 2gh
v = √(2gh)
Assuming g = 9.81m/s^2
v = √(19.62h)
4 main components are: Nitrogen, Oxygen, Argon and water vapour
<span>The forces of nature are phase forces.</span>
You have three known variables:
Acceleration -

Time -

Initial Velocity -

For the first part of your question:

For the second part of your question:

This still needs to be converted to m/h:
I think it might be a or d i hope i have helped :)