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tatuchka [14]
2 years ago
15

What is the name of the perceived change in a sound wave’s frequency due to motion between the observer and the sound source?

Physics
2 answers:
andrew11 [14]2 years ago
6 0

Answer: The answer is Doppler effect.

Explanation:

When there is a relative motion between the source and the observer then there will be change in the frequency of the wave. This phenomenon is called Doppler effect.

For example,when the source and the observer are moving each other then the frequency increases in this case. When the source and the observer are moving away from other then the frequency decreases in this case.

Therefore, Doppler effect is the name of the perceived change in a sound wave's frequency due to motion between the observer and the sound source.

Shkiper50 [21]2 years ago
4 0

Answer: Hello mate!

the name is "doppler effect"

As you may know, the frequency (and hence the wavelength) of the sound determines the pitch.

If you move towards the source of the sound, the wavelenght seems shorter, which means that the frequency is higher, and also the pitch.

In the other case, if you are moving away from the sound, the wavelength seems larger and the frequency smaller, so the pitch is lower.

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Why is it not necessary for radio telescope surfaces to be as smooth as a mirror?
Law Incorporation [45]
It doesn't on account of radio waves are longer than optical waves. Radio waves are a sort of electromagnetic radiation with wavelengths in the electromagnetic range longer than infrared light. These long waves are in the radio locale of the electromagnetic range.
8 0
3 years ago
How many ohms of resistance must be present in a circuit that has 240 volts and a current of 15 amps?
PIT_PIT [208]

Answer:

16 ohms

Explanation:

V= I ⋅ R

where,  V  is the net potential difference in the circuit,  I  is the current in the circuit and  R  is the net resistance of the circuit.  

In this case,  V = 240  volts,  I = 15  amperes.

240 = 15 ⋅ R  

⇒ R = 240/ 15 = 16  ohms

5 0
3 years ago
Read 2 more answers
Activity
vodka [1.7K]
Your welcome LOL plz like

5 0
2 years ago
Vector A has a magnitude of 30 units. Vector B is perpendicular to vector Aand has a magnitude of 40 units. What would the magni
Fudgin [204]

Answer:

|\vec A + \vec B| = 50 units

Explanation:

As we know that magnitude of two vectors is given as

|\vec A + \vec B| = \sqrt{A^2 + B^2 + 2AB cos\theta}

here we know that

A = magnitude of vector A

B = magnitude of vector B

\theta = angle between two vectors

so here we know that

A = 30 units

B = 40 units

angle = 90 degree

so we have

|\vec A + \vec B| = \sqrt{30^2 + 40^2 + 2(30)(40)cos90}

|\vec A + \vec B| = \sqrt{30^2 + 40^2}

|\vec A + \vec B| = 50 units

3 0
2 years ago
The device used to measure a masses of a body is kilogram . true or false​
olga nikolaevna [1]

Answer: false

Explanation:

While kilograms are the unit used to measure body mass, the device used is a scale.

Hope it helps :)

6 0
2 years ago
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