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2 years ago

Practicing soccer skills works most muscles groups. True Or False

Physics

2 answers:

Yakvenalex [24]2 years ago

5 0

Answer:

I'd say true, it does exercise and work most major muscle groups .

Explanation:

defon2 years ago

4 0

Answer:

True

Explanation:

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g Two identical metal spheres (small enough to be treated as particles) each with a mass of 3.1 × 10−3 kg are hung from separate

gogolik [260]

Answer:

Explanation:

Let q be the charges on each spheres , 2d be the distance between them in equilibrium , T be tension in the string and F be the force of repulsion between them

F = k q² /4d²

For equilibrium

T sin15 = F

T cos 15 = mg

tan15 = F / mg

F = mg tan15

k q² /4d² = mg tan15

k q² = 4d² x mg tan15

= 4 x( .7 sin15)² x 3.1 x 10⁻³ x 9.8 x .2679

= 1.068 x 10⁻³

q = .3444 x 10⁻⁶ C

no of electrons

= .3444 x 10⁻⁶ / 1.6 x 10⁻¹⁹

= 215.25 x 10¹⁰

8 0

3 years ago

The magnetic field at the center of a wire loop of radius , which carries current , is 1 mT in the direction (arrows along the w

Citrus2011 [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The magnetic field is $B_{net} = \frac{1}{4} * mT$

And the direction is $-\r k$

Explanation:

From the question we are told that

The magnetic field at the center is $B = 1mT$

Generally magnetic field is mathematically represented as

$B = \frac{\mu_o I}{2R}$

We are told that it is equal to 1mT

$B = \frac{\mu_o I}{2R} = 1mT$

From the first diagram we see that the effect of the current flowing in the circular loop is (i.e the magnetic field generated)

$\frac{\mu_o I}{2R} = 1mT$

This implies that the effect of a current flowing in the smaller semi-circular loop is (i.e the magnetic field generated)

$B_1 = \frac{1}{2} \frac{\mu_o I}{2R}$

and for the larger semi-circular loop is

$B_2 = \frac{1}{2} \frac{\mu_o I}{2 * (2R)}$

Now a closer look at the second diagram will show us that the current in the semi-circular loop are moving in the opposite direction

So the net magnetic field would be

$B_{net} = B_1 - B_2$

$= \frac{1}{2} \frac{\mu_o I}{2R} -\frac{1}{2} \frac{\mu_o I}{2 * (2R)}$

$=\frac{\mu_o I}{4R} -\frac{\mu_o I }{8R}$

$=\frac{\mu_o I}{8R}$

$= \frac{1}{4} \frac{\mu_o I}{2R}$

Recall $\frac{\mu_o I}{2R} = 1mT$

$B_{net} = \frac{1}{4} * mT$

Using the Right-hand rule we see that the direction is into the page which is $-k$

3 0

3 years ago

Which bird on the wire, the one with a mass of 50g or the one with a mass of 60g, has the most potential energy?

Fynjy0 [20]

Answer:

one with 60g have the more potential

Explanation:

5 0

3 years ago

Do geochemists need to have a knowledge of physical science? Explain your<br> answer. please help:))

saul85 [17]

No they don’t lol I hate school

6 0

3 years ago

Which part of the ear sends a message to the brain that is recognized as sound?

viva [34]

The auditory nerve carries an electrical signal to the brain, which turns it into a sound that we recognize and understand.

5 0

3 years ago