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4 years ago

Which produces more carbon dioxide?

1 answer:

6 0

It depends on the car and the home and what it is producing but most commonly it would be cars producing more carbon dioxide.

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The equation P^xV^yT^z= constant is Boyle law for what is the values of x,y,z

chubhunter [2.5K]

I learned the equation as P•V=k•T .

So x=1, y=1, and z= -1 .

3 0

3 years ago

Which figure represents the electric field lines of two negative point charges?<br> Help

Yuliya22 [10]

Answer:

The question is incomplete because the options are not given. We'll solve this question with the options.

There are two properties of negative charges which we have to consider to find the figure of its electrical field.

Firstly, for a negative charge, the electrical field lines are always directed radially outwards and they don't intersect.

Secondly, we know that similar charges repel each other, so there will be no electrical field present directly between these two negative charges. Electrical field line will be present between two charges only when there is a force of attraction.

Taking both of these facts into consideration, the electrical field line between two negatives is represented by the figure below.

3 0

4 years ago

Particle-X has a speed of 0.720 c and a momentum of 4.350x1019 kgm/s. What is the mass of the particle? 2.0206 10-27 kg Hints: T

kirill115 [55]

Explanation:

Given that,

Speed of particle = 0.720 c

Momentum = 4.350\times10^{-19}\ kgm/s[/tex]

(I). We need to calculate the mass of the particle

Using formula of momentum

$P=mv$

$m =\dfrac{P}{v}$

$m=\dfrac{4.350\times10^{-19}}{ 0.720\times3\times10^{8}}$

$m=2.013\times10^{-27}\ Kg$

We need to calculate the rest mass of particle

Using formula of rest mass

$m=\dfrac{m_{0}}{\sqrt{1-(\dfrac{v}{c})^2}}$

Where, $m_{0}$ = rest mass

Put the value into the formula

$m_{0}=2.013\times10^{-27}\times\sqrt{1-(\dfrac{0.720 c}{c})^2}$

$m_{0}=2.013\times10^{-27}\times\sqrt{1-(0.720)^2}$

$m_{0}=1.4\times10^{-27}\ kg$

(b). We need to calculate the rest energy of the particle

Using formula of energy

$E_{0}=m_{0}c^2$

Put the value into the formula

$E_{0}=1.4\times10^{-27}\times(3\times10^{8})^2$

$E_{0}=1.26\times10^{-10}\ J$

(c). We need to calculate the kinetic energy of the particle

Using formula of kinetic energy

$K.E=mc^2-m_{0}c^2$

$K.E=(m-m_{0})\timesc^2$

$K.E=(2.013\times10^{-27}-1.4\times10^{-27})\times3\times10^{8}$

$K.E=1.84\times10^{-19}\ J$

(d). We need to calculate the total energy of the particle

Using formula of energy

$E=mc^2$

Put the value into the formula

$E=2.013\times10^{-27}\times(3\times10^{8})^2$

$E=1.812\times10^{-10}\ J$

Hence, This is the required solution.

8 0

3 years ago

If a 375 mL sample of water was cooled from 37.5 C to 0 C how much heat wad lost in joules

harkovskaia [24]

1 mL = 1 gram
Q=375*4.179*37.5

3 0

3 years ago

Read 2 more answers

What is the temperature change of 1.0 mol of a monotomic gas if its thermal energy is increased by 1.0 J ? Express your answer i

natali 33 [55]

Answer: 0.08K

Explanation:

When temperature changes, the corresponding change in thermal energy of a gas is given by:

ΔE (thermal) = 3/2nRΔT

Defining the parameters:

ΔE (thermal) = Increase in thermal energy of the mono atomic gas = 1.0J

n = number of moles of the gas = 1.0mol

R = Ideal gas constant = 8.314J/mol/K

ΔT = change in temperature. This is what we need to find.

Rearranging the equation to make ΔT subject of the formula,

ΔT= 2 x ΔE (thermal) / (3 x n x R)

Therefore, ΔT = 2 x 1.0J / (3 x 1.0mol x 8.314J/mol/K)

ΔT = 2.0J / 24.942J/K

ΔT = 0.0802K

ΔT = 0.08K

The temperature change of 1.0mol of a monoatomic gas if its thermal energy is increased by 1.0J is 0.08K.

7 0

3 years ago