Question

A 100kg crate slides along a floor with a starting velocity of 21ms If the force due to friction is 8N how long will it take for the box to come to rest? Show your work!

Answer 1

A 100kg crate slides along a floor with a starting velocity of 21 m/s. If the force due to friction is 8N, then, it will take 262.5 s for the box to come to rest.

We'll begin by calculating the declaration of the box. This can be obtained as follow:

Force (F) = –8 N (opposition)

Mass (m) = 100 Kg

Deceleration (a) =?

F = ma

–8 = 100 × a

Divide both side by 1000

$a = \frac{-8}{100}$

a = –0.08 ms¯²

Therefore, the deceleration of the box is –0.08 ms¯²

Finally, we shall determine the time taken for the box to come to rest. This can be obtained as follow:

Deceleration (a) = –0.08 ms¯²

Initial velocity (u) = 21 ms¯¹

Final velocity (v) = 0 ms¯¹

Time (t) =.?

v = u + at

0 = 21 + (–0.08×t)

0 = 21 – 0.08t

Collect like terms

0 – 21 = –0.08t

–21 = –0.08t

Divide both side by –0.08

$t = \frac{-21}{-0.08}$

t = 262.5 s

Therefore, it will take 262.5 s for the box to come to rest.

Learn more: brainly.com/question/14446351