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Tanya [424]
3 years ago
15

When the reaction was carried out the calculated theoretical yield for water was 176 grams but the measured yield was 148 grams

what is the percent yield
Chemistry
1 answer:
kaheart [24]3 years ago
7 0

Answer:

84.09 %.

Explanation:

This would be (148/176) * 100

= 0.8409 * 100

= 84.09 %.

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Given the unbalanced equation below, answer the following: Calculate the number of liters of 3.00 M lead (II) iodide solution pr
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The number of liters of 3.00 M lead (II) iodide : 0.277 L

<h3>Further explanation</h3>

Reaction(balanced)

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From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :

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Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):

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