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kenny6666 [7]
3 years ago
12

What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chem

ical equation below?
H2SO4 --> 2 H+ + SO42-
Chemistry
1 answer:
Ainat [17]3 years ago
4 0

Answer:  0.002 M

Explanation:

The balanced chemical equation for ionization of H_2SO_4 in water is:

H_2SO_4\rightarrow 2H^++SO_4^{2-}

According to stoichiometry :

1 mole of H_2SO_4 ionizes to give =2 mole of H^+ ions

0.001 mole of H_2SO_4 ionizes to give = \frac{2}{1}\times 0.001=0.002 mole of H^+ ions

Thus H^+ of a solution of 0.001 M aqueous sulfuric acid is 0.002 M

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Given :

An atom of a certain element has 12 protons, 14 neutrons, and 2 valence electrons.

To Find :

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What is the term for a solid that forms when two solutions are mixed?
Inessa [10]

Option D

A precipitate is the term for a solid that forms when two solutions are mixed

<u>Explanation:</u>

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A cylindrical glass tube of length 27.4cm and radius 4 cm is filled with gas. The empty tube has a mass of 254.3 g. The tube fil
Temka [501]

Density of the gas is 3.05 × 10⁻³ g / cm³.

<u>Explanation:</u>

Volume of the cylinder = π r² h

where r is the radius and h is the height of the height or the length of the glass tube.

Here r = 4 cm and h = 27.4 cm

Volume of the cylinder = 3.14 × 4 × 4 × 27.4 = 1376.6 cm³

We have to find the mass of the gas by subtracting the mass of the tube filled with the substance from the mass of the empty tube.

Mass of the substance = 258.5 - 254.3 = 4.2 g

We have to find the density using the formula as,

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$ Density = \frac{4.2}{1376.6}

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So the Density of the gas is 3.05 × 10⁻³ g / cm³.

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