Question

What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chemical equation below?
H2SO4 --> 2 H+ + SO42-

Answer 1

Answer:  0.002 M

Explanation:

The balanced chemical equation for ionization of $H_2SO_4$ in water is:

$H_2SO_4\rightarrow 2H^++SO_4^{2-}$

According to stoichiometry :

1 mole of $H_2SO_4$ ionizes to give =2 mole of $H^+$ ions

0.001 mole of $H_2SO_4$ ionizes to give = $\frac{2}{1}\times 0.001=0.002$ mole of $H^+$ ions

Thus $H^+$ of a solution of 0.001 M aqueous sulfuric acid is 0.002 M