Mercury (ii) oxide is made up of mercury and oxygen. The total mass of mercury (ii) oxide is 14.2 g, after decomposition 13.2 g of mercury were formed, therefore the mass of oxygen 1 g (14.2 g -13.2 g).
Percentage of oxygen = (1/14.2)×100 = 7.04%
Percentage of mercury = (13.2/14.2) × 100 = 92.96%
Therefore, percentage composition of the compound, oxygen is 7.04% and mercury is 92.96%.
Answer:
0.99mol/L
Explanation:
Molarity ( M) = # of moles of solute / volume of solution (L)
Volume of Solution = 100 mL or 0.1 L
Molarity ( M) = # of moles of solute / volume of solution (L)
Molarity (M) = 0.099 mol / 0.1 L = 0.99mol/ L
a covalent bond and an ionic bond. An ionic bond if formed from the transfer of electrons from the outer shell of atoms. ... An example of this is NaCl, where the sodium atom becomes Na+ due to the loss of electrons, and the chlorine atom becomes the negatively charged chloride (Cl-).
