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2 years ago

9

HELP HELP ME PLSS

1 answer:

Akimi4 [234]2 years ago

6 0

Answer:

the average answer in maybe 60

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each body cell of a goldfish contains 94 chromosomes.how many chromosomes are contained in a goldfish sex cell?

Shalnov [3]

47 I believe not 100% sure

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2 years ago

Given each pair, complete the sentences to determine which member of each has the stronger intermolecular dispersion forces.

evablogger [386]

Answer:

CH3CH2CH2Cl

CH3CH2CH2CH2CH2SH

Br2

Explanation:

Dispersion forces increases with increase in relative molecular mass. The specie having the greater relative molecular mass definitely has greater dispersion forces. A rough estimation of the relative molecular masses of the species stated in the answer will reveal this fact.

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3 years ago

Whats 2736 +832091 +09281

astra-53 [7]

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5 0

3 years ago

fish tank initially contains 35 liters of pure water. Brine of constant, but unknown, concentration of salt is flowing in at 5 l

weeeeeb [17]

Answer:

Therefore, the rate of change in the amount of salt is $\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$

$\frac{grams }{min}$

Explanation:

Given:

Initial volume of water $V = 35$ lit

Flowing rate = 5 $\frac{Lit}{min}$

The rate of change in the amount of salt is given by,

$\frac{dx}{dt} =$ ( Rate of salt enters tank - rate of sat leaves tank )

Since tank is initially filled with water so we write that,

$x(0) = 0$

Let amount of salt in the solution is $c$ ,

$\frac{dx}{dt} = \frac{5c}{1 } - \frac{x(t) \times 5}{100}$

$\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$ $\frac{grams}{min}$

Therefore, the rate of change in the amount of salt is $\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$

$\frac{grams }{min}$

7 0

3 years ago

12. The vapor pressure of water at 90°C is 0.692 atm. What is the vapor pressure (in atm) of a solution made by dissolving 3.68

luda_lava [24]

Answer : The vapor pressure (in atm) of a solution is, 0.679 atm

Explanation : Given,

Mass of $H_2O$ = 1.00 kg = 1000 g

Moles of $CsF$ = 3.68 mole

Molar mass of $H_2O$ = 18 g/mole

Vapor pressure of water = 0.692 atm

First we have to calculate the moles of $H_2O$ .

$\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{1000g}{18g/mole}=55.55mole$

Now we have to calculate the mole fraction of $H_2O$

$\text{Mole fraction of }H_2O=\frac{\text{Moles of }H_2O}{\text{Moles of }H_2O+\text{Moles of }CsF}=\frac{55.55}{55.55+3.68}=0.938$

Now we have to partial pressure of solution.

According to the Raoult's law,

$P_{Solution}=X_{H_2O}\times P^o_{H_2O}$

where,

$P_{Solution}$ = vapor pressure of solution

$P^o_{H_2O}$ = vapor pressure of water = 0.692 atm

$X_{H_2O}$ = mole fraction of water = 0.938

$P_{Solution}=X_{H_2O}\times P^o_{H_2O}$

$P_{Solution}=0.938\times 0.692atm$

$P_{Solution}=0.649atm$

Therefore, the vapor pressure (in atm) of a solution is, 0.679 atm

5 0

2 years ago