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Anton [14]
3 years ago
7

What causes a siamese cat to have dark fur on some parts of its body?

Physics
1 answer:
larisa86 [58]3 years ago
3 0

Answer

The colder areas of its body are darker in color (extremities)  

Explanation:

Siamese cats fur is darker in the cooler parts of the skin (extremities), such as ears, nose, tail and paws. Conversely, warmer parts of the body were associated with white- or light grey-colored fur. Moreover, Siamese cats have a highly recognized 'mask' on their face for the same reason.

Hope this help If it did plz mark brainliest

Have a nice day!!

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What is the magnitude of fs on an object lying on a flat surface without moving, on
Degger [83]

The magnitude of the force acting on the object lying on a flat surface without moving is 10 N.

The given parameters;

  • magnitude of force on the object, F = 10 N
  • angle between the object and the horizontal flat surface = 0⁰

Apply Newton's second law of motion to determine the magnitude of the force on the object.

Due to the position of the object, the magnitude of the force acting on it is calculated as;

\Sigma F_{net} = F\sin(\theta ) + F cos(\theta)\\\\\Sigma F_{net} = 10 sin(0) + 10cos(0)\\\\\Sigma F_{net} = 10 \ N

Therefore, the magnitude of the force acting on the object is 10 N.

Learn more here: brainly.com/question/19887955

7 0
2 years ago
A 50kg boy runs at a speed of 10.0m/s and jumpsonto a cart
andriy [413]

Answer:

the mass of the cart is 150 kg

Explanation:

given,

mass of boy(m) = 50 kg

speed of boy (v)= 10 m/s                  

initial velocity of cart (u) = 0                    

final velocity of cart(V) = 2.5 m/s              

mass of the cart(M) = ?                              

m v + M u = (m + M ) V......................(1)

50× 10 + 0 = (50 + M ) 2.5

M =\dfrac{500}{2.5} - 50

M = 150 Kg                                          

hence, the mass of the cart is 150 kg

4 0
3 years ago
Read 2 more answers
What type of galaxy is shown?
dexar [7]
Elliptical, because the shape of the galaxy isn’t like the others. It is unique to its own and doesn’t have another to compare to
8 0
3 years ago
Read 2 more answers
A heat pump is to be used for heating a house in winter. The house is to be maintained at 70°F at all times. When the temperatur
Anna35 [415]

Answer:

\dot{W_{H} } = 4244.48 Btu/h

Explanation:

Temperature of the house, T_{H} = 70^{0} F

Convert to rankine, T_{H} = 70^{0}+ 460 = 530 R

Heat is extracted at 40°F i.e T_{L} = 40^{0}F  = 40 + 460 = 500 R

Calculate the coefficient of performance of the heat pump, COP

COP = \frac{T_{H} }{T_{H} - T_{L}  } \\COP = \frac{530 }{530 - 500  }\\ COP = \frac{530}{30} \\COP = 17.67

The minimum power required to run the heat pump is given by the formula:

\dot{W_{H} } = \frac{\dot{Q_{H} }}{COP} \\...............(*)

Where the heat losses from the house, \dot{Q_{H} } = 75,000 Btu/h

Substituting these values into * above

\dot{W_{H} } = \frac{75000}{17.67} \\ \dot{W_{H} } = 4244.48 Btu/h

3 0
3 years ago
51. Suppose you measure the terminal voltage of a 3.200-V lithium cell having an internal resistance of 5.00Ω by placing a 1.00-
Tanya [424]

Explanation:

Given that,

Terminal voltage = 3.200 V

Internal resistance r= 5.00\ \Omega

(a). We need to calculate the current

Using rule of loop

E-IR-Ir=0

I=\dfrac{E}{R+r}

Where, E = emf

R = resistance

r = internal resistance

Put the value into the formula

I=\dfrac{3.200}{1.00\times10^{3}+5.00}

I=3.184\times10^{-3}\ A

(b). We need to calculate the terminal voltage

Using formula of terminal voltage

V=E-Ir

Where, V = terminal voltage

I = current

r = internal resistance

Put the value into the formula

V=3.200-3.184\times10^{-3}\times5.00

V=3.18\ V

(c). We need to calculate the ratio of the terminal voltage of voltmeter equal to emf

\dfrac{Terminal\ voltage}{emf}=\dfrac{3.18}{3.200 }

\dfrac{Terminal\ voltage}{emf}= \dfrac{159}{160}

Hence, This is the required solution.

5 0
3 years ago
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