All categories

3 years ago

What causes a siamese cat to have dark fur on some parts of its body?

Physics

1 answer:

larisa86 [58]3 years ago

3 0

Answer

The colder areas of its body are darker in color (extremities)

Explanation:

Siamese cats fur is darker in the cooler parts of the skin (extremities), such as ears, nose, tail and paws. Conversely, warmer parts of the body were associated with white- or light grey-colored fur. Moreover, Siamese cats have a highly recognized 'mask' on their face for the same reason.

Hope this help If it did plz mark brainliest

Have a nice day!!

You might be interested in

Which piece of evidence did Alfred Wegener use to develop the theory of continental drift?

Eduardwww [97]

The right answer for the question that is being asked and shown above is that: "A.tectonic activity concentrated in certain areas." A piece of evidence did Alfred Wegener use to develop the theory of continental drift is that <span>A.tectonic activity concentrated in certain areas</span>

3 0

3 years ago

Which of the following is true about teeth in mammals? a. Only large mammals have teeth. b. All teeth in mammals look the same a

katovenus [111]

<span>c. Mammal teeth do different jobs and are different sizes and shapes</span>

4 0

3 years ago

Who is the first person to trace the characteristics of successive generations of a living thing?

Andrei [34K]

Gregor Mendel was the first person to trace the characteristics of successive generations of a living thing.

7 0

3 years ago

Read 2 more answers

Wile E. Coyote is holding a "HEAVY DUTY ACME™ ANVIL" on a cliff that is 40.0 meters high. The Roadrunner (beep-beep), who is 1.0

Mariana [72]

Answer:

53.8

Explanation: I plugged it on the formula

3 0

2 years ago

A car with mass 950 kg and a speed of 16 m/s approaches an intersection. A 1300 kg minivan traveling at 21 m/s is heading for th

Alex73 [517]

Answer:

$V_f = 13.8863 \angle 60.89\°$

Explanation:

Our values are,

$m_1 = 950Kg\\v_1 = 16m/s \\m_2 =1300Kg\\v_2 = 21m/s$

We have all the values to apply the law of linear momentum, however, it is necessary to define the two lines in which the study will be carried out. Being an intersection the vehicle of mass m_1 approaches through the X axis, while the vehicle of mass m_2 approaches by the y axis. In the collision equation on the X axis, we despise the velocity of object 2, since it does not come in this direction.

$m_1v_1=(m_1+m_2)v_fcos\theta$

For the particular case on the Y axis, we do the same with the speed of object 1.

$m_2v_2=(m_1+m_2)v_fsin\theta$

By taking a final velocity as a component, we can obtain the angle between the two by relating the equations through the tangent

$Tan\theta = \frac{m_2v_2}{m_1v_1}\\Tan\theta = \frac{1300*21}{950*16}\\\theta = tan^{-1}(1.7960)\\\theta = 60.89\°$

Replacing in any of the two functions, given above, we will find the final speed after the collision,

$(950)(16)=(950+1300)V_fcos(60.89)$

$V_f= \frac{(950)(16)}{(950+1300)cos(60.89)}$

$V_f = 13.8863 \angle 60.89\°$

8 0

3 years ago