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Mariana [72]
2 years ago
12

Luigi twirls a round piece of pizza dough overhead with a frequency of

Physics
1 answer:
viva [34]2 years ago
5 0

The linear speed of the pepperoni is 0.628 m/s. Its direction is tangential to the circle.

We know that;

v = rω

r = radius of the piece = 10 cm or 0.1 m

ω = angular velocity

We have to convert 60 revolutions per minute to radians per second

1 rev/min = 0.10472 rad/s

60 revolutions per minute = 60 rev/min × 0.10472 rad/s/1 rev/min

= 6.28 rad/s

v =  0.1 m ×  6.28 rad/s

v = 0.628 m/s

The direction of this velocity is tangential to the circle.

Learn more: brainly.com/question/4612545

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A proton, mass 1.67 × 10−27 kg and charge +1.6 × 10−19 c, moves in a circular orbit perpendicular to a uniform magnetic field of
stellarik [79]

Time taken by proton to complete one complete circular orbit= 7.28 x 10⁻⁸ s

Explanation:

For proton, the centripetal force required for circular motion is provided by the magnetic force,

so Fm= Fc

q v B = m v²/r

m= mass of charged particle

v= velocity

B =magnetic field

q= charge

r= radius of circular path

v= q B r/m

now v= r ω

ω= angular velocity

ω r = q B r /m

ω=q B /m

now ω= 2π/T where T =time period

so 2π/T=q B/m

T= 2 πm/q B

T= 2π (1.67 x 10⁻²⁷)/ [( 1.6 x 10⁻¹⁹)* (0.9)]

T= 7.28 x 10⁻⁸ s

6 0
3 years ago
Formula One racers speed up much more quickly than normal passenger vehicles, and they also can stop in a much shorter distance.
klasskru [66]

Answer:

The magnitude of the car's acceleration as it slows during braking is 36.81 m/s²

Explanation:

From the question, the given values are as follows:

Initial velocity, u = 90 m/s

final velocity, v = 0 m/s

distance, s = 110 m

acceleration, a = ?

Using the equation of motion, v² = u² + 2as

(90)² + 2 * 110 * a = 0

8100 + 220a = 0

220a = -8100

a = -8100/220

a = -36.81 m/s²

The value for acceleration is negative showing that car is decelerating to a stop. The magnitude of the car's acceleration as it slows during braking is therefore 36.81 m/s²

4 0
3 years ago
The speed of a boat undergoing constant acceleration increases from 5 meters per second to 15 meters per second over a period of
defon
Should be 250m. check with your teacher and let me know

4 0
3 years ago
What is the formula to find PE and KE ?
Lapatulllka [165]
PE stands for Potential Energy. It is the stored energy in an object due to its position with respect to some reference. It is expressed in Joules.

P.E = m * g * h    OR  P.E. = mgh

m - mass of the body
g - acceleration due to gravity
h - height attained due to the body's displacement.

K.E. stands for Kinetic Energy. It is the energy possessed by a body due to its motion.

K.E = 1/2 mv²    where m = mass of the body; v = velocity with which the body is moving.
5 0
2 years ago
Assuming no air resistance, how far will a 0.0010 kg raindrop have fallen when it hits the ground 30.0 s later. Assume g = 9.8 m
Serga [27]
D = (1/2)·at²
where d is the distance fallen, a is the acceleration (g in this problem), and t is the time
d = (1/2)·(9.8 m/s²)·(30 s)² = (1/2)·(9.8)·(900) m
d = 4410 m
The answer is b) 4410 m

Note: the mass of the raindrop is irrelevant since the acceleration due to gravity is independent of mass. (Galileo's Leaning Tower of Pisa experiment)
6 0
3 years ago
Read 2 more answers
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