Ok so v is the velocity. Assuming it is constant, v = 2m/s
At 6 seconds x= 12.0m
Answer: Hello! Here your answer......
Force = 10.244 Newtons
b) No of oscillations = 0.88
Explanation:
Since the block executes SHM we can write it's position as function of time as
ω is the natural frequency of the system
A is the amplitude of the system
Thus accleration of the block
Thus using the given values at t= 3.50 sec we can calculate the acceleration as
thus force can be calculated using newtons second law as
b)
Now no of oscillations can be obtained as
no of oscillations in 3.50 seconds = 3.50/3.976 = 0.88
Hope this helps! (Brainly)♥
Answer:
11970 pa
Explanation:
A millimetre of mercury is a manometric unit of pressure, formerly defined as the extra pressure generated by a column of mercury one millimetre high, and currently defined as exactly 133.322387415 pascals so if 1 mmHg is 133 pa 90mmHg is 11970 aprox
The correct formula for calculating the tangential speed of an orbiting object is V(t)=wr.
V(t)= Tangential Speed
w= Angular Velocity
r= Radius of the Path
Hope this helps.
