the independent variable is what you're testing or changing in an experiment, so the answer is the temperature of the ball when its dropped.
i hope that helped <3
I think it’s C. But I’m not completely sure.
<span>Radius, the distance from the centre = 0.390
Electric field is equal to half of the magnitude. E2 = E / 2
Given
E1 = E2
E1 = k x Q / r^2
E2 = (k x Q / r2^2) / 2
Equating the both we get 2 x r^2 = r2^2
r2 = square root of (2 x r1^2) = square root of (2) x r = 1.414 x 0.390
r2 = 1.414 x 0.390 = 0.551 m</span>
The power generated by the students will be .
•Work done is equal to
Mgh = 90*9.8*1.5
1587.6 j
thus power is equal to work done by time
1587.6/3
529.2 j/secs
