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Lerok [7]
4 years ago
14

Suppose you were making 100.0 mL of a solution that is 0.040 M KCl. What mass of KCl should you weigh to make this solution?

Chemistry
1 answer:
scZoUnD [109]4 years ago
3 0

Answer:

mass = 0.2982 grams

Explanation:

Given that;

volume = 100.0 mL = 0.1 L

Molarity =0.040 M

Since Molarity = \frac{no of moles }{volume}

0.040 M = \frac{x}{0.1}

(x) no of moles = 0.040 × 0.1

= 0.004 moles

Also; to calculate the  mass of KCl should you weigh to make this solution;

we have;

no of moles =\frac{mass}{molar mass}

molar mass of KCl = 74.55 g/mol

∴

0.004 moles = \frac{mass}{74.55g/mol}

mass = 0.004 moles * 74.55 \frac{g}{mol}

mass = 0.2982 grams

Hence, the mass of KCl should you weigh to make this solution is  0.2982 grams

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Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]       ......(1)

where,

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m_2 = mass of solution 2 (liquid water) = 29.0 g

T_{final} = final temperature = ?

T_1 = initial temperature of solution 1 = 25°C  = [273 + 25] = 298 K

T_2 = initial temperature of solution 2 = 45°C  = [273 + 45] = 318 K

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Putting values in equation 1, we get:

50.0\times 4.18\times (T_{final}-298)=-[29.0\times 4.18\times (T_{final}-318)]\\\\T_{final}=305.3K

Converting this into degree Celsius, we use the conversion factor:

T(K)=T(^oC)+273

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