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777dan777 [17]
3 years ago
15

Use Lewis theory to determine the chemical formula for the compound formed between Sr and N.

Chemistry
1 answer:
mariarad [96]3 years ago
8 0

Answer:

Sr_3N_2

Explanation:

Hello,

In this case, since the Lewis theory is based on the bonds formation between atoms via the valence electrons, we can verify the chemical formula of the compound formed by strontium and nitrogen by noticing that strontium has two valence electrons as it is in group IIA, for that reason, two nitrogens should be available for bonding. Therefore, since nitrogen is in group VA, it is said that three electrons are required to attain the octet (maximum amount bonded electrons), for that reason, three strontiums are should be available for bonding. In such a way, the formula should be:

Sr_3N_2

Regards.

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Mass and energy are conserved Question 13 options: A) only in chemical changes. B) always in physical changes and sometimes in c
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3 years ago
Please help !!
ipn [44]

<u>Answer:</u>

<u>For 2:</u> The % yield of the product is 92.34 %

<u>For 3:</u> 12.208 L of carbon dioxide will be formed.

<u>Explanation:</u>

  • <u>For 2:</u>

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100              ......(1)

Given values:

Actual value of the product = 78.4 g

Theoretical value of the product = 84.9 g

Plugging values in equation 1:

\% \text{yield}=\frac{78.4 g}{84.9g}\times 100\\\\\% \text{yield}=92.34\%

Hence, the % yield of the product is 92.34 %

  • <u>For 3:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(2)

Given mass of carbon dioxide = 24 g

Molar mass of carbon dioxide = 44 g/mol

Plugging values in equation 1:

\text{Moles of carbon dioxide}=\frac{24g}{44g/mol}=0.545 mol

<u>At STP conditions:</u>

1 mole of a gas occupies 22.4 L of volume

So, 0.545 moles of carbon dioxide will occupy = \frac{22.4L}{1mol}\times 0.545mol=12.208L of volume

Hence, 12.208 L of carbon dioxide will be formed.

5 0
3 years ago
0.89kg is equivalent to
ahrayia [7]
1.96 pounds, i hope this helped.
3 0
3 years ago
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