The question is as follows: What is the% m / m of a solution in which 22 g of solute are dissolved in 44 g of solvent?
Answer: The% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.
Explanation:
Given: Mass of solute = 22 g
Mass of solvent = 44 g
The percentage m/m is calculated using the following formula.
Substitute the values into above formula as follows.
Thus, we can conclude that the% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.
Answer:
235/92U+10n→144/54Xe+90/38Sr+2/10n
Explanation:
- The nuclear reaction for the neutron-induced fission of u−235 to form xe−144 and sr−90 is represented by;
235/92U+10n→144/54Xe+90/38Sr+2/10n
- In nuclear fission reactions a heavy nuclide is split into two light nuclides and is coupled by the release of energy.
False, as oceans can act as carbon sinks along with forests.
Hydrocarbons are a type of organic compound. Hydrocarbons contains a carbon, hydrogen and oxygen bond that makes it
organic. Chlorides, carbonates and nitrous oxides are not organic compounds but
they are inorganic compounds.
Answer:
Light energy; chemical
Explanation:
The light energy of the Sun is converted into chemical energy by the plants.
