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Snezhnost [94]
3 years ago
6

Identify the NMR term that corresponds to each description.

Chemistry
1 answer:
balandron [24]3 years ago
4 0

Answer:

A- upfield

B- down field

C- splitting

D- chemical shift

E- integration

Explanation:

NMR is a spectroscopic technique commonly used to observe the magnetic fields around the nucleus of atoms in a compound under investigation.

A chemical shift is the difference in parts per million (ppm) between the resonance frequency of the observed protons in the compound under study and that of the tetramethylsilane (TMS) (the reference compound in NMR with a chemical shift of zero ppm because all protons in the compound are equivalent).

If signals appear close to the reference signal, the signals are said to appear upfield. If the signals appear far away from the reference, they are said to appear down field.

The presence of protons cause splitting of peaks to the magnitude of n+1. n is the number of neighboring protons. Splitting refers to the appearance of multiple peaks for a single nucleus due to neighboring nuclei.

The area of a signal that corresponds to the number of nuclei at that frequency is called the integration.

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3 years ago
You have separate solutions of HCl and H2SO4 with the same concentrations in terms of molarity. You wish to neutralize a solutio
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Answer: Option (A) is the correct answer.

Explanation:

A neutralization reaction is defined as the reaction in which an acid reacts with a base to yield salt and water.

The given reaction will be as follows.

         HCl + NaOH \rightarrow NaCl + H_{2}O

       H_{2}SO_{4} + 2NaOH \rightarrow Na_{2}SO_{4} + 2H_{2}O

Now, if molarity of NaOH = M_{1} and volume of NaOH = V_{1}

Therefore, Molarity of HCl = molarity of H_{2}SO_{4} = M_{2}

     Volume of HCl required = \text{molarity of NaOH} \times \frac{\text{volume of NaOH}}{\text{molarity of HCl}}

                 = \frac{M_{1}V_{1}}{M_{2}}

So, vVolume of H_{2}SO_{4} required = 0.5 x molarity of NaOH x \frac{\text{volume of NaOH}}{\text{molarity of H_{2}SO_{4}}}[/tex]

                       = 0.5 \times \frac{M_{1}V_{1}}{M_{2}}

Hence, volume of HCl = 2 x volume of H_{2}SO_{4}.

Thus, we can conclude that HCl solution would be required more volume (in mL) to neutralize the base.

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