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mezya [45]
3 years ago
6

Water has a density that is 13.6 times less than that of mercury. If an undersea vessel descends to 1.6 km, how much pressure do

es the water exert in atm?
Physics
1 answer:
vova2212 [387]3 years ago
4 0

Answer:

155.25 atm

Explanation:

Distance, h = 1.6 km = 1600 m

density of water = 13.6 times less than the density of mercury

density of mercury = 13.6 x 10^3 kg/m^3

So, density of water = 1 x 10^3 kg/m^3

Pressure exerted by the water

P = distance x density of water x acceleration due to gravity

P = 1600 x 1000 x 9.8

P=1.568\times10^{8}Pa

We know that

1 atm = 1.01 x 10^5 Pa

So, P=1.568\times10^{8}Pa = P=\frac{1.568\times10^{8}}{1.01\times10^{5}}=155.25 atm

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PLEASSE HELP WILL MARK BRAINLIEST!!!!!!!!!!
faust18 [17]
They are halogen elements, or nonmetallic elements in the same GROUP, specifically group 17
6 0
3 years ago
The drag force on a falling coffee filter can be modeled as a linear function with respect to velocity, F⃗ D =−bv, where b is a
nordsb [41]

Newton's second law and graphical analysis allow us to find the correct answer for the measure of the constant b is:

    D) Stack several filters to change the mass measure the acceleration of the system.

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the bodies.  

         ∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

They indicate that the drag force on the filters is

         F = - b v

Where b is a positive constant that depends on the shape and area of ​​the filter and v is the speed of the filter.

Let's write Newton's second law.

         W - fr  = ma

         W -bv  = ma

         

In the experiment the students indicate that they can measure the position, velocity and acceleration of the body.

Based on the above, if we place several filter weights and measure their speed and acceleration in each case, we can make a graph of velocity versus acceleration, we can take the value of the constant b from the slope.

Let's analyze the different answers:

A) False. The constant b depends on the shape of the filter therefore it must be kept constant.

B) False. The constant depends on the area, so it must be kept constant.

C) May be. In this case, since we have the terminal velocity, the acceleration is zero, Newton's second law remains.

                    B v - W = 0

                    b = \frac{W}{v}  

The problem with the method is the difficulty of measuring the compression terminal velocity.

D) True. According to the discussion of the velocity versus acceleration. graph, the constant b is equal to the slope of the graph.

E) May be. The problem with this method is finding a reliable value for the terminal velocity.

In conclusion, using Newton's second law and graphical analysis we can find the correct answer for the measure of the constant b is:

 D) Stack several filters to change the mass measure the acceleration of the system.

Learn more here:  brainly.com/question/2441565

6 0
2 years ago
A girl rides her bike at 2.52 m/s on the way to her friends how which is 628 m away.
Harrizon [31]

Answer: 249 seconds

Explanation:

Speed of bike = 2.52 m/s

Distance = 628 m

Time taken = ? ( let the unknown value be Z)

Recall that speed is the distance covered per unit time.

Hence, speed = Distance / Time taken

Time taken = Distance / speed

Z = 628m / 2.52 m/s

Z = 249.2 seconds (Round to nearest tenth i.e 249 seconds)

Thus, it takes 249 seconds for the girl to get to her friends house

7 0
3 years ago
An electric dipole is formed from two charges, ±q, spaced 0.800 cm apart. The dipole is at the origin, oriented along the y-axis
Simora [160]

Answer: q = 2.781e-9C = 2.781nC

E=200C

Explanation:

E = Qd/(2πEor^3)

Where

E=Electric field intensity

Q=Charge

d=distance between the dipole=0.008m

Eo=permitivitty

400 N/C = Q(0.80e-2 m)/(2πε*(10e-2 m)^3)

Q= (400* 2* 3.142 * 8.85 x 10-12 * 0.1^3)/0.008

q = 2.781e-9C = 2.781nC

b)

Though the dipole are two separate charges. And since the point is on the x-axis, the electric field strengths are equivalent. The magnitude of the vector sum is:

E = kq*2sin θ/r^2

= 2(8.99e9 N*m^2/C^2)(2.781e-9 C)*sin(arctan(.4/10))/(10e-2 m)^2

= 2(8.99e9) * (2.781e-9) * sin(2.290)/(10e-2 m)^2

=200 C

3 0
3 years ago
HELP PLEASE HERE IS THE IMAGE
kari74 [83]

Answer:

I am pretty sure it's E because it splits through every layer

3 0
3 years ago
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