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aliina [53]
2 years ago
14

Trong mặt phẳng Oxy, chất điểm chuyển động với phương trình Tìm quĩ đạo của chất điểm.

Physics
1 answer:
QveST [7]2 years ago
6 0

Xin lỗi nhưng tôi cần ảnh để trả lời đúng câu hỏi của bạn, thưa ông.

Nếu bạn đăng lại với hình ảnh, tôi sẽ sẵn lòng giúp đỡ!

JSYK khi cố gắng tìm quỹ đạo mà bạn luôn muốn biết thời tiết nó đi theo hướng Đông Nam Bắc hoặc Tây

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An intravenous (IV) system is supplying saline solution to a patient at the rate of 0.06 cm3/s through a needle of radius 0.2 mm
horsena [70]

Answer:

Pressure applied to the needle is 7528 Pa

Explanation:

As we know by poiseuille's law of flow of liquid through a cylindrical pipe

the rate of flow through the pipe is given as

Q = \frac{\Delta P \pi r^4}{8\eta L}

now we know that

Q = 0.06 \times 10^{-6} m^3/s

radius = 0.2 mm

Length = 6.32 cm

\eta = 1\times 10^{-3} Pa s

now we have

6 \times 10^{-8} = \frac{\Delta P \pi (0.2 \times 10^{-3})^4}{8(1 \times 10^{-3})6.32 \times 10^{-2}}

3.03 \times 10^{-11} = \Delta P 5.02 \times 10^{-15}

\Delta P = 6028 Pa

now we have

P - 1500 = 6028 Pa

P = 7528 Pa

8 0
2 years ago
calculate the period of a wave whose frequency is 5 Hertz and whose wavelength is one centimeter give your answer in a decimal f
olga2289 [7]
The period of the wave is the reciprocal of its frequency.

       1 / (5 per second)  =  0.2 second .

The wavelength is irrelevant to the period.  But since you
gave it to us, we can also calculate the speed of the wave.

Wave speed = (frequency) x (wavelength)

                   = (5 per second) x (1cm)  =  5 cm per second
4 0
3 years ago
A cubical block of iron 10 cm on each side is floating on mercury in a vessel. (i) What is the height of the block above the mer
Gre4nikov [31]

Answer:

i 5.3 cm ii. 72 cm

Explanation:

i

We know upthrust on iron = weight of mercury displaced

To balance, the weight of iron = weight of mercury displaced . So

ρ₁V₁g = ρ₂V₂g

ρ₁V₁ = ρ₂V₂ where ρ₁ = density of iron = 7.2 g/cm³ and V₁ = volume of iron = 10³ cm³ and ρ₂ = density of mercury = 13.6 g/cm³ and V₂ = volume of mercury displaced = ?

V₂ = ρ₁V₁/ρ₂ = 7.2 g/cm³ × 10³ cm³/13.6 g/cm³ = 529.4 cm³

So, the height of iron above the mercury is h = V₂/area of base iron block

= 529.4 cm³/10² cm² = 5.294 cm ≅ 5.3 cm

ρ₁V₁g = ρ₂V₂g

ii

ρ₁V₁ = ρ₃V₃ where ρ₁ = density of iron = 7.2 g/cm³ and V₁ = volume of iron = 10³ cm³ and ρ₃ = density of water = 1 g/cm³ and V₃ = volume of water displaced = ?

V₃ = ρ₁V₁/ρ₃ = 7.2 g/cm³ × 10³ cm³/1 g/cm³ =  7200 cm³

So, the height of column of water is h = V₃/area of base iron block

= 7200 cm³/10² cm² = 72 cm

7 0
3 years ago
How can you find the nuetrons in youre element ??
miskamm [114]

Answer: you subtract the number of protons from the mass number, on the periodic table your atomic number is your protons and your atomic mass is the mass number

Explanation:

5 0
2 years ago
What study did james e hansen focus on
Brut [27]
James E. Hansen studied climate change
6 0
1 year ago
Read 2 more answers
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