Explanation:
For equilibrium,
.
So,
= 0
![T_{1} = \frac{8 \times mg}{10}](https://tex.z-dn.net/?f=T_%7B1%7D%20%3D%20%5Cfrac%7B8%20%5Ctimes%20mg%7D%7B10%7D)
= ![\frac{8 \times 90 \times 9.8}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B8%20%5Ctimes%2090%20%5Ctimes%209.8%7D%7B10%7D)
= 705.6 N
Also, for equilibrium
= 0
= 0
or, ![T_{2} = mg - T_{1}](https://tex.z-dn.net/?f=T_%7B2%7D%20%3D%20mg%20-%20T_%7B1%7D)
= ![90 \times 9.8 - 705.6](https://tex.z-dn.net/?f=90%20%5Ctimes%209.8%20-%20705.6)
= 176.4 N
Thus, we can conclude that the tension in the first rope is 176.4 N.
The answer that is being described above is the ASTEROIDS. The one that we see floating between Mars and Jupiter is what we call the Asteroid Belt. The asteroid belt comprises of different rocky bodies and they also orbit within the solar system. Hope this helps.
determining how data will he gathered
Explanation: Apex
Answer:
The time it will take for the car to reach a velocity of 28 m/s is 7 seconds
Explanation:
The parameters of the car are;
The acceleration of the car, a = 4 m/s²
The final velocity of the car, v = 28 m/s
The initial velocity of the car, u = 0 m/s (The car starts from rest)
The kinematic equation that can be used for finding (the time) how long it will take for the car to reach a velocity of 28 m/s is given as follows;
v = u + a·t
Where;
v = The final velocity of the car, v = 28 m/s
u = The initial velocity of the car = 0 m/s
a = The acceleration of the car = 4 m/s²
t = =The time it will take for the car to reach a velocity of 28 m/s
Therefore, we get;
t = (v - u)/a
t = (28 m/s - 0 m/s)/(4 m/s²) = 7 s
The time it will take for the car to reach a velocity of 28 m/s, t = 7 seconds.
Answer:
reference against doubt
Explanation:
exact standards of measurement are a reference point for situations in doubt , a line against which to test and observe.