Answer:
R = 31.9 x 10^(6) At/Wb
So option A is correct
Explanation:
Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A
Thus; R = L/μA,
Now from the question,
L = 4m
r_1 = 1.75cm = 0.0175m
r_2 = 2.2cm = 0.022m
So Area will be A_2 - A_1
Thus = π(r_2)² - π(r_1)²
A = π(0.0225)² - π(0.0175)²
A = π[0.0002]
A = 6.28 x 10^(-4) m²
We are given that;
L = 4m
μ_steel = 2 x 10^(-4) Wb/At - m
Thus, reluctance is calculated as;
R = 4/(2 x 10^(-4) x 6.28x 10^(-4))
R = 0.319 x 10^(8) At/Wb
R = 31.9 x 10^(6) At/Wb
Answer:
Gravitational force (pulled downward by the Earth)
Normal force (pushed upward by the ground)
Applied force (pushed by the person)
Friction force (pulled opposite the direction of motion by the roughness of the ground)
Answer:
atomic radius R = 0.157 nm
metal atomic weight = 72.27 g/mol
Explanation:
given data
parameters a = 0.413 nm
parameters b = 0.665 nm
parameters c = 0.876 nm
atomic packing factor = 0.536
density = 3.99 g/cm³
to find out
atomic radius and atomic weight
solution
we apply here atomic packing factor (x) that is
atomic packing factor (x) = 
..................1
put here value we get
atomic packing factor = 
R = 
R = 
atomic radius R = 0.157 nm
and
now we get here metal atomic weight that is
metal atomic weight = 
....................2
metal atomic weight = 
metal atomic weight = 72.27 g/mol
