Answer:
It will not experience fracture when it is exposed to a stress of 1030 MPa.
Explanation:
Given
Klc = 54.8 MPa √m
a = 0.5 mm = 0.5*10⁻³m
Y = 1.0
This problem asks us to determine whether or not the 4340 steel alloy specimen will fracture when exposed to a stress of 1030 MPa, given the values of <em>KIc</em>, <em>Y</em>, and the largest value of <em>a</em> in the material. This requires that we solve for <em>σc</em> from the following equation:
<em>σc = KIc / (Y*√(π*a))</em>
Thus
σc = 54.8 MPa √m / (1.0*√(π*0.5*10⁻³m))
⇒ σc = 1382.67 MPa > 1030 MPa
Therefore, the fracture will not occur because this specimen can handle a stress of 1382.67 MPa before experience fracture.
Answer:
Coal required is 101 Teragram/year.
Coal saved is 25.25 Teragram/year.
Explanation:
1 Teragram is exactly 1000000000 kilograms.
Answer:

Explanation:
The model for the turbine is given by the First Law of Thermodynamics:

The turbine power output is:

The volumetric flow is:


The specific volume of steam at inlet is:
State 1 (Superheated Steam)

The mass flow is:



Specific enthalpies at inlet and outlet are, respectively:
State 1 (Superheated Steam)

State 2 (Saturated Vapor)

The turbine power output is:


Answer:
#include<iostream>
using namespace std;
int main()
{
double data[3][5],avg,least,most,total;
int leastNum,mostNum;
for(int i=0;i<3;i++)
{
cout<<"Enter quantity of food for monkey "<<i+1<<":\n";
for(int j=0;j<5;j++)
{
cout<<"Day "<<j+1<<": ";
cin>>data[i][j];
}
}
least = data[0][0];
most = data[0][0];
for(int i = 0;i<3;i++)
{
for(int j = 0;j<5;j++)
{
total+=data[i][j];
if(data[i][j]>most)
{
most=data[i][j];
mostNum=i+1;
}
if(data[i][j]<least)
{
least=data[i][j];
leastNum=i+1;
}
}
}
avg=total/5.0;
cout<<"Average food eaten in a day by all the 3 monkeys: "<<avg<<endl;
cout<<"Most amount of food eaten in a day: "<<most<<" by monkey: "<<mostNum<<endl;
cout<<"Least amount of food eaten in a day: "<<least<<" by monkey: "<<leastNum<<endl;
return 0;
}
Answer:
b hope it's help you heart me and please give brainlesst