Psychologist who uses behavioral approach to therapy would probably try which of the following
2 answers:
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Answer:
It falls at the same speed in both cases.
Explanation:
If I were standing still the phone would be in free fall after slipping out of my hand.
I set a frame of reference with origin on the ground and the positive Y axis pointing up.
It would slip at t0 = 0, from a position Y0 = 5 ft, with a speed of Vy0 = 0.
It would be subject to an gravitational acceleration of -32.2 ft/s^2.
Since acceleration is constant:
Y(t) = Y0 + Vy0 * t + 1/2 * 4 * t^2
When it hits the floor at t1 it will be at Y(t1) = 0
0 = 5 + 0 * t1 - 16.1 * t1^2
16.1 * t1^2 = 5
t1^2 = 5 / 16.1
If the elevator is standing still it would take 0.55 s to hit the ground.
Now, if the elevator is moving up at 10 ft/s.
The frame of reference will have its origin at the place the floor of the elevator is at t = 0, and stay there as the elevetor moves. The floor of trhe elevator will have a position of Ye = 10 * t
Vy0 = 10 ft/s because it will be moving initially at the same speed as the elevator.
And it will hit the floor of the elevator not at 0, but at
Ye = 10 * t2
So:
10 * t2 = 5 + 10 * t2 - 16.1 * t2^2
0 = 5 - 16.1 * t2^2
16.1 * t1^2 = 5
t1^2 = 5 / 16.1
It falls at the same speed in both cases.
Answer:
Check the explanation
Explanation:
Electrical current can be measured according to the rate of electric charge flow in any electrical circuit:
the derivative of the electric charge by time determines the momentary current.
i(t) will be the momentary current I at time t in amps (A).
Q(t) will also be the momentary electric charge in coulombs (C).
t is the time in seconds (s).
so if the current is constant:
I = ΔQ / Δt
I will be the current in amps (A).
ΔQ will be the electric charge in coulombs (C), which is expected to flows at time duration of Δt.
Δt is the time duration in seconds (s).
Kindly check the attached image below to get the step by step explanation to the question above.
