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3 years ago

To Separate camphor from sand we use_______process.

Chemistry

1 answer:

Molodets [167]3 years ago

3 0

Answer:

<h3><em>to Separate camphor from sand we use <u>sublimation</u> process.</em></h3><h3 /><h3 /><h3><em>Hope </em><em>it</em><em> </em><em>is </em><em>helpful</em><em> to</em><em> you</em><em> </em></h3>

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Matter that has a definite volume but no definite shape is a

Zielflug [23.3K]

I think it’s A for the first one and C for the second one

4 0

3 years ago

molecular orbital theory correctly predicts paramagnetism according to mo theory, overlap of two p atomic orbitals produces .oxy

Mkey [24]

Overlap of two p atomic orbital produces oxygen gas ,o2 because it has two unpaired electron and explains paramagnetism.

O2 molecules have two unpaired electrons Materials in which all the electrons are paired are diamagnetic. It repel a magnetic field.Para magnetic and diamagnetic materials do not act as permanent magnets. Molecular orbital theory provides an explanation of chemical bond that explains paramagnetism of the oxygen molecule. It also explains the bonding in a other molecule. O2 molecule has two unpaired electron. Electrons creates magnetic field as it goes to the ground state and also spin.MO theory describes the distribution of electrons in molecules same as the distribution of electrons in atoms described using atomic orbital.

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1 year ago

The carbon-carbon double bond in ethene is ________ and ________ than the carbon-carbon triple bond in ethyne.

lbvjy [14]

Answer:

weaker and longer

Explanation:

Since there are 3 bonds in ethyne in comparision with the 2 bonds of ethyne between carbon atoms, they are attracted more to each other → the bond gets shorter . And since there are one more bond that supports the union → the bond gets stronger

thus the carbon-carbon double bond in ethene is weaker and longer than the carbon-carbon triple bond in ethyne

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3 years ago

A certain reaction at equilibrium has more moles of gaseous products than of gaseous reactants.(b) Write a statement about the r

mojhsa [17]

To be equal as $K_p$ , $K_c$ needs to be divided by $(RT)^{\Delta n}$

<h3>Briefly explained</h3>

When the amount of gaseous reactant is greater than the amount of gaseous product, where $n_{products} < n_{reactants}$ ,

then = $K_p < K_c$

It's because $\Delta n$ is negative, which places (RT) in the denominator. This is how the equation will now appear.

$K_p = K_c(RT)^{-\Delta n} = \frac{ K_c}{(RT)^{\Delta n}}$

Here you can observe the value of $K_c$ is greater than $K_p$ . To be equal as $K_p$ , $K_c$ needs to be divided by $(RT)^{\Delta n}$

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.

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6 0

2 years ago

The atomic number is

vovikov84 [41]

It’s D I’m pretty sure

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3 years ago

To Separate camphor from sand we use_______process.​

To Separate camphor from sand we use_______process.