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svetoff [14.1K]
2 years ago
10

To Separate camphor from sand we use_______process.​

Chemistry
1 answer:
Molodets [167]2 years ago
3 0

Answer:

<h3><em>to Separate camphor from sand we use <u>sublimation</u> process.</em></h3><h3 /><h3 /><h3><em>Hope </em><em>it</em><em> </em><em>is </em><em>helpful</em><em> to</em><em> you</em><em> </em></h3>
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If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
Alinara [238K]

Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This is the value of  the heat capacity of the Calorimeter.

7 0
3 years ago
3 waves are shown with a line through their center. The bottom of the first wave is labeled C. A bracket labeled D connects the
Likurg_2 [28]

Answer:Label the parts of this wave.

A:  

✔ crest

B:  

✔ amplitude

C:  

✔ trough

D:  

✔ wavelength

Explanation:

8 0
2 years ago
Read 2 more answers
What is the pH for a 0.10 M HCI solution at 25<br> degreesCelsius?
11Alexandr11 [23.1K]

Answer:

1.0

Explanation:

Hydrochloric acid is a strong acid, that is, an acid that dissociates completely, according to the following reaction.

HCl(aq) → H⁺(aq) + Cl⁻(aq)

Then, the concentration of H⁺ will be equal to the initial concentration of the acid, i.e., 0.10 M.

We can calculate the pH using the following expression.

pH = -log [H⁺] = -log 0.10 = 1.0

3 0
3 years ago
HCl(?) + H2O(?) → H3O+(?) + Cl-(?)
larisa86 [58]

Answer:

Transcribed image text: Answer.

the following question for the mixing of gaseous hydrogen chloride with water to make hydrochloric acid. HCl) + H2O(2) → H30*) + Cl (2) What is the phase label on HCI? aq

6 0
2 years ago
Find the total number of moles of ions produced when 0.347 mol of sodium carbonate dissolves.
Ahat [919]

Answer:

molarity= 0.238 mol L-

Explanation:

The idea here is that you need to use the fact that all the moles of sodium phosphate that you dissolve to make this solution will dissociate to produce sodium cations to calculate the concentration of the sodium cations.

Na 3 PO 4 (aq) → Na + (aq) + PO3−4 (aq)

Use the molar mass of sodium phosphate to calculate the number of moles of salt used to make this solution.

3.25g⋅1 mole N 3PO4 163.9g = 0.01983 moles Na3 PO 4

Now, notice that every

1 mole of sodium phosphate that you dissolve in water dissociates to produce

3bmoles of sodium cations in aqueous solution.

4 0
2 years ago
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