Explanation:
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Answer: BOTH ARE TRUE
Explanation: Nondestructive testing or Evaluation is a term used in the field of science and technology to describe the evaluations, analysis or testing carried out on components of materials without destroying any part or components of the test materials. It is very useful in scientific research or industrial engineering environments. When any disruption of physical structure or configuration of a component will lead to discontinuing of the test, and it may not affect the usefulness of the affected parts.
Answer:
d
Explanation:
when one variables is zero ,the other is also zero
Density d=m/V
mass m=d.V=13.5×5=67.5g
m=67.5g
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<span>Answer: Va = 7,625 m/s
Vb = 7,404 m/s
Given:
A = 486,000 m
B = 901,000 m
G = 6.67428E-11 m^3/kg-s^2
M = 5.9736E+24 kg
r = 6,371,000 m
Recall that you need the actual orbital distance from the *center* of the Earth, giving radius plus altitude:
rA = 6,857,000 m
rB = 7,272,000 m
Equation:
V = SQRT { GM / r }
Solve for A
Va = SQRT { [ (6.67428E-11 m^3/kg-s^2) * (5.9736E+24 kg) ] / (6,857,000 m) }
Va = SQRT { [ 3.9869 m^3/s^2 ] / (6,857,000 m) }
Va = SQRT { 58,144,202 m^2/s^2 }
Va = 7,625 m/s
Solve for B
Vb = SQRT { [ (6.67428E-11 m^3/kg-s^2) * (5.9736E+24 kg) ] / (7,272,000 m) }
Vb = SQRT { [ 3.9869 m^3/s^2 ] / (7,272,000 m) }
Vb = SQRT { 54,826,016 m^2/s^2 }
Vb = 7,404 m/s</span>
