All categories

2 years ago

Is the momentum of a 0.1 kg Mass moving with a velocity of 5 miles per second West

Physics

2 answers:

Vsevolod [243]2 years ago

8 0

Momentum = mass times velocity

0.1 kg x 5 miles per second West

= 804.7 kg-meters/sec West .

dem82 [27]2 years ago

6 0

<span>Momentum equals Mass x Velocity
Mass equals 0.1kg
Velocity equals 5m/s

So the momentum has to = 0.1 x 5 = 0.5kgm/s

I hope this helped
</span>

You might be interested in

at the sewing store, ava bought a bag of buttons. 21 in all. 21 of the buttons were large. what percentage of the buttons wre la

erma4kov [3.2K]

If she only has 21 buttons and all 21 of them are large, then all of her buttons are large. so 100% of the buttons would be large.

6 0

3 years ago

Read 2 more answers

Emily is a competitive swimmer. Why does wearing a swim cap help Emily swim faster?

sladkih [1.3K]

Answer:

It's helps Emily became when she swims her hair is not in the way creating friction and making her swim faster. friction acts between two metals blocks that slide past each other.

Explanation:

6 0

2 years ago

A ball is thrown upward from ground level at a velocity of 55.5 m/s. What is the ball maximum height?

ollegr [7]

I believe the answer is 153.8 m.

5 0

2 years ago

To practice problem-solving strategy 22.1: gauss's law. an infinite cylindrical rod has a uniform volume charge density ρ (where

BabaBlast [244]

Let say the point is inside the cylinder

then as per Gauss' law we have

$\int E.dA = \frac{q}{\epcilon_0}$

here q = charge inside the gaussian surface.

Now if our point is inside the cylinder then we can say that gaussian surface has charge less than total charge.

we will calculate the charge first which is given as

$q = \int \rho dV$

$q = \rho * \pi r^2 *L$

now using the equation of Gauss law we will have

$\int E.dA = \frac{\rho * \pi r^2* L}{\epcilon_0}$

$E. 2\pi r L = \frac{\rho * \pi r^2* L}{\epcilon_0}$

now we will have

$E = \frac{\rho r}{2 \epcilon_0}$

Now if we have a situation that the point lies outside the cylinder

we will calculate the charge first which is given as it is now the total charge of the cylinder

$q = \int \rho dV$

$q = \rho * \pi r_0^2 *L$

now using the equation of Gauss law we will have

$\int E.dA = \frac{\rho * \pi r_0^2* L}{\epcilon_0}$

$E. 2\pi r L = \frac{\rho * \pi r_0^2* L}{\epcilon_0}$

now we will have

$E = \frac{\rho r_0^2}{2 \epcilon_0 r}$

7 0

3 years ago

Calcium (Ca) is in the second column of the periodic table and is classified as an alkaline earth metal. Which of the following

enot [183]

Answer:

CaI2

Explanation:

4 0

2 years ago