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jeka57 [31]
3 years ago
10

You hold your physics textbook in your hand. (Assume that no other objects are in contact with the book.)

Physics
1 answer:
horrorfan [7]3 years ago
5 0

1.

Answer:

Hand on book

Earth on book

Explanation:

Since we are holding the book so the forces that acts on the book is

1. Hand on book

this is the contact force between hand and the book

2. Earth on book

here this is the gravitational attraction force of earth on the book

2.

Answer:

A. book on hand  - NA

B. hand on book  - upwards

C. floor on book  - NA

D. earth on book - downwards

Explanation:

Since book is holding in hand so at equilibrium position we can say that the forces on the book must be in equilibrium

so first of all the force of attraction due to earth on the book is downwards and this is counterbalanced by the force of hand on book which is upwards.

3.

Answer:

A. book on hand  

Explanation:

As per Newton's III law we know that every action has equal and opposite reaction.

so if our hand apply the force on the book in upward direction then book will apply same magnitude force on the hand in downward direction.

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zlopas [31]

Answer: The area of brick in contact with the floor is 1539 cm^{3}.

Explanation:

Given: Length = 19 cm

Width = 9 cm

Height = 9 cm

As the brick is rectangular in shape. Hence, its area will be calculated as follows.

Area = length \times width  \times height

Substitute the values into above formula as follows.

Area = length \times width  \times height\\= 19 cm \times 9 cm \times 9 cm\\= 1539 cm^{3}

Thus, we can conclude that area of brick in contact with the floor is 1539 cm^{3}.

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2 years ago
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2 years ago
A proton moves with a speed of 1.00 x 106 m/s perpendicular to a magnetic field, B. As a result, the proton moves in circle of r
Softa [21]

Answer:

0.0109 m ≈ 10.9 mm

Explanation:

proton speed = 1 * 10^6 m/s

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<u>determine the radius of the circle in which an electron would move </u>

we will apply the formula for calculating the centripetal force for both proton and electron ( Lorentz force formula)

For proton :

Mp*V^2 / rp  = qp *VB   ∴  rp = Mp*V / qP*B    ---------- ( 1 )

For electron:

re = Me*V/ qE * B -------- ( 2 )

Next: take the ratio of equations 1 and 2

re / rp = Me / Mp                                 ( note: qE = qP = 1.6 * 10^-19 C )

∴ re ( radius of the electron orbit )

= ( Me / Mp ) rp

= ( 9.1 * 10^-31 / 1.67 * 10^-27 ) 20

= ( 5.45 * 10^-4 ) * 20

= 0.0109 m ≈ 10.9 mm

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