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jeka57 [31]
3 years ago
10

You hold your physics textbook in your hand. (Assume that no other objects are in contact with the book.)

Physics
1 answer:
horrorfan [7]3 years ago
5 0

1.

Answer:

Hand on book

Earth on book

Explanation:

Since we are holding the book so the forces that acts on the book is

1. Hand on book

this is the contact force between hand and the book

2. Earth on book

here this is the gravitational attraction force of earth on the book

2.

Answer:

A. book on hand  - NA

B. hand on book  - upwards

C. floor on book  - NA

D. earth on book - downwards

Explanation:

Since book is holding in hand so at equilibrium position we can say that the forces on the book must be in equilibrium

so first of all the force of attraction due to earth on the book is downwards and this is counterbalanced by the force of hand on book which is upwards.

3.

Answer:

A. book on hand  

Explanation:

As per Newton's III law we know that every action has equal and opposite reaction.

so if our hand apply the force on the book in upward direction then book will apply same magnitude force on the hand in downward direction.

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Explanation:

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2. Moving ocean water exerts a force of 375 N on a boat, causing the boat to move a distance of 34.7 m in 8.34 s. What power doe
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For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg
viva [34]

Answer:

The magnetic field is 1.16 T.  

Explanation:

speed, v = 10% of speed of light = 3 x 10^7 m/s

diameter, d = 54 cm

radius, r = 0.27 m

charge, q = 1.6 x 10^-19 C

mass, m = 1.67 x 10^-27 kg

Let the magnetic field is B.

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qvB=\frac{mv^2}{r}\\\\B =\frac{mv}{qr}\\\\B =\frac{1.67\times 10^{-27}\times 3\times 10^{7}}{1.6\times 10^{-19}\times 0.27}\\\\B =1.16 T

6 0
2 years ago
What magnitude charge creates a 1.0 n/c electric field at a point 1.0 m away?
Stolb23 [73]

Answer:

1.1\cdot 10^{-10}C

Explanation:

The electric field produced by a single point charge is given by:

E=k\frac{q}{r^2}

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

In this problem, we have

E = 1.0 N/C (magnitude of the electric field)

r = 1.0 m (distance from the charge)

Solving the equation for q, we find the charge:

q=\frac{Er^2}{k}=\frac{(1.0 N/c)(1.0 m)^2}{9\cdot 10^9 Nm^2c^{-2}}=1.1\cdot 10^{-10}C

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2 years ago
Where is the frequency of ultrasound in relation to the range of human ability to hear
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Answer:

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Explanation:

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