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igomit [66]
2 years ago
9

Suppose a snack bar is burned in a calorimeter and heats 2,000 g water by 20 °C. How much heat energy was released? (Hint: Use t

he specific heat equation.) Give your answer in both joules and calorie
Chemistry
2 answers:
GenaCL600 [577]2 years ago
7 0

Answer:

Explanation:

Remember that the key is the water so

using the formula q=m*s*deltT

We have the mass 2000g

we have the specific heat of water which is 1.00 cal/ g C

and the final temperature 20 C

Remember that delt T is the change in temperature meaning (Tfinal - Tinitial) Assuming that the water is at room  temperature (25 C)  before starting the reaction then

q= (2000 g)(1.00 cal/g C)(20-25)

q= -10, 000 cal  

if you want you can convert to joules by multiplying by 4.314 J

In more simpler terms - If all the heat released was absorbed by the water, and it takes 1 calorie of heat to raise

the temperature of 1 gram of water by 1°C that is a total of 20 times 2000 or 40,000 cal.

or 40 kilocalories. If you want it in joules, there are 4.184 joules to one calorie so it is

4.184 times 40 or 167.36 kilojoules.

Hope that helped

Salsk061 [2.6K]2 years ago
6 0

The answer is: 167360

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The decomposition of NI3 to form N2 and I2 releases −290.0 kJ of energy. The reaction can be represented as 2NI3(s)→N2(g)+3I2(g)
EastWind [94]

Answer:

-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.

Explanation:

Mass of nitrogen triiodide = 20.0 g

Moles of nitrogen triiodide = \frac{20.0 g}{395 g/mol}=0.05063 mol

2NI_3(s)\rightarrow N_2(g)+3I_2(g), \Delta H_{rxn}=-290.0 kJ

According to reaction, 2 moles of nitrogen triiodide gives 290.0 kilo Joules of heat on decomposition ,then 0.05063 moles of nitrogen triiodide will give :

\frac{-290.0 kJ}{2}\times 0.05063=-7.34 kJ

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3 years ago
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Answer:

Here:

Explanation:

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<h3>Further explanation</h3>

Given

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Required

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Solution

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<u><em>~ LadyBrain</em></u>

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