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4 years ago

What is one or two letter character used to identify an element

Physics

2 answers:

Greeley [361]4 years ago

4 0

A symbol of the element. hope this helps!!

Murljashka [212]4 years ago

3 0

Its the symbol it usually has the first letter of the elements name.

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A metal sphere of radius 11 cm has a net charge of 2.8 × 10–8 C. (a) What is the electric field at the sphere's surface? (b) If

harina [27]

Answer:

Therefore,

a) $E=20.82\ kN/C$

b) $V= 2290\ Volt$

c) distance from the sphere's surface = 1.8 cm

Explanation:

Given:

Radius, r = 11 cm = 0.11 m

Charge, $Q = 2.8\times 10^{-8}\ C$

To Find:

a) electric field at the sphere's surface = ?

b) If V = 0 at infinity, what is the electric potential at the sphere's surface = ?

c) At what distance from the sphere's surface has the electric potential decreased by 320 V = ?

Solution:

Electric field at the sphere's surface is given as,

$E=\dfrac{k\times Q}{r^{2}}$

Where,

E = Electric Field,

$k = Coulomb's\ constant = 9\times 10^{9}$

Q = Charge

r = Radius

Substituting the values we get

$E=\dfrac{9\times 10^{9}\times 2.8\times 10^{-8}}{(0.11)^{2}}=20.82\ kN/C$

Now, Electric Potential at point surface is given as,

$V=\dfrac{k\times Q}{r}$

Substituting the values we get

$V=\dfrac{9\times 10^{9}\times 2.8\times 10^{-8}}{0.11}=2.29\ kV$

For distance from the sphere's surface has the electric potential decreased by 320 V,

So V becomes,

V = 2290 - 320 = 1970 Volt, then r =?

$V=\dfrac{k\times Q}{r}$

Substituting the values we get

$r=\dfrac{k\times Q}{V}\\\\r=\dfrac{9\times 10^{9}\times 2.8\times 10^{-8}}{1970}=0.128\ m$

Therefore the distance from the sphere's surface,

$d = 12.8 - 11 = 1.8\ cm$

Therefore,

a) $E=20.82\ kN/C$

b) $V= 2290\ Volt$

c) distance from the sphere's surface = 1.8 cm

7 0

4 years ago

3. A car has an acceleration of +2m/s2. What does this tell you about the velocity of the car? What

Anna35 [415]

Answer:

acceleration is the rate of change of velocity

therefore in the above statement, the velocity increases twice per second.

when acceleration is negative, then it is accelerated motion.

ie. the car accelerates twice per second

7 0

3 years ago

You and your friend are going bungee jumping! You wait directly below them with a camera. When they leap from the bridge they be

Alex

Answer:

The amplitude is $A = 90.2 \ m$

Explanation:

From the question we are told that

The frequency of when sound is approaching observer is $f = 392 Hz$

The frequency as the move away from observer is $f_ a = 330 \ Hz$

The time between the pitch are $t = 10 \ s$

Here you are the observer and your friends are the source of the sound

The period is mathematically evaluated as

$T = 2 t$

as it is the time to complete one oscillation which from on highest pitch to the next highest pitch

Now T can also be mathematically represented as

$T = \frac{2 \pi}{w}$

Where $w$ is the angular velocity

=> $\frac{2 \pi}{w} = 2 * 10$

=> $w = 0.314 \ rad/sec$

Now using Doppler Effect,

The source of the sound is approaching the observer

The

$f = f_o (\frac{v}{v- wA} )$

$392 = f_o (\frac{v}{v- wA} )$

Where A is the amplitude

So when the source is moving away from the observer

$f_a = f_o (\frac{v}{v+ wA} )$

$330 = f_o (\frac{v}{v+ wA} )$

Here $f_o$ is the fundamental frequency

Dividing the both equation we have

$\frac{392}{330} = \frac{f_o(\frac{v}{v-wA} )}{f_o(\frac{v}{v+wA}}$

$1.1878 = \frac{v+wA}{v-wA}$

$1.1878 v - 1.1878 wA = v+wA$

$1.1878 v = 2.1878 wA$

=> $A = \frac{(0.1878 * (330))}{(2.1878)* (0.314)}$

$A = 90.2 \ m$

7 0

3 years ago

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kolbaska11 [484]

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8 0

4 years ago

If two vectors are 7 cm and 5 cm .then what's the addition of these two?

wariber [46]

Answer:

7 + 5 = 12

Explanation:

Since it asks for 2 vectors, you have to add 2 times.

8 0

3 years ago