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adelina 88 [10]
3 years ago
8

When the resistance in a circuit remains constant, how are the voltage and current related?

Physics
2 answers:
solmaris [256]3 years ago
6 0
V=IR, therefore when resistance is constant the voltage and current are directly proportional
docker41 [41]3 years ago
5 0

Answer:

if the resistance is constant the voltage and current are directly proportional

Explanation:

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Hey Tori's are the rim of a canyon yells hello toward the opposite side she has an echo hello four seconds later if the speed of
krek1111 [17]

Answer:

The wall is 680 meter away from the person.

Explanation:

Given data

Speed of sound = 340 \frac{m}{s}

Given that Persons said hello toward the opposite side she has an echo hello 4 seconds later means it takes 2 seconds for the sound to reach the wall & again 2 seconds to reach the persons ear.

Therefore the distance between the person & wall is

D = speed × Time

D = 340 × 2

D = 680 meter

Therefore the wall is 680 meter away from the person.

6 0
3 years ago
How do you label <br> Time= energy • power
Lana71 [14]

First of all, that equation is not correct, which may be the reason
that you're having trouble assigning units to the quantities.

Power is defined as [energy / time],  so  [Energy] = [ power x time ],
and
         [Time] = [ energy / power ].

Unit-wise, these equations are correct just as they appear here,
with no proportionality constants or conversion factors, when ...

[ Power ] = watts
[ Energy ] = joules
[ Time ] = seconds .
 

5 0
2 years ago
Which of the following is neutral?
Sauron [17]

Answer:

atoms and neutrons

Explanation:

electrons have a negative charge

protons have a positive charge

cations are positive ions

anions are negative ions

4 0
3 years ago
Read 2 more answers
You have a 78.7 mF capacitor initially charged to a potential difference of 11.5 V. You discharge the capacitor through a 3.03 Ω
Aloiza [94]

Answer:

\tau=0.23\;second

Explanation:

Given,

C=78.7\;mF\\V=11.5\;V\\R=3.03\;\Omega\\

Time constant

\tau=RC\\\tau=78.7\times10^{-3}\times3.03\\\tau=238.461\times10^{-3}\;second\\\tau=0.23\;second

8 0
3 years ago
Find the velocity (in m/s) of a proton that has a momentum of 4.96 X 10^-19 kg.m/s.
kramer

Answer:

The velocity of the proton is 2.965*10^{8} \frac{m}{s}

Explanation:

The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:

p=m*v Equation (1)

Where:

p: Is the momentum in kg*m/s

m: Is mass of the particle in kg

v: Is the velocity of the particle in m/s

Data known:

m= 1,6726 × 10^–27 kg : mass of the proton

p= 4.96 X 10^-19 kg.m/s.

We replace this data in the Equation (1):

4,96*10^{-19} =1.6726*10^{-27} *vv=\frac{4.9*10^{-19} }{1.6726*10^{-27} }

v=(\frac{4.96}{1.6726} )*(10^{27-19} )

v=2,965*10^{8} m/s

Answer: The velocity of the proton is 2.965*10^{8} \frac{m}{s}

3 0
3 years ago
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