Answer:
K = 25351. 69 N / m
Explanation:
Given : Fk = 515 N , v = 1.8 m /s , d = 5.0 m , β = 22.0 ° , m = 150 kg
Using the work done by all forces at initial and the end can determine the constant of the spring
Ws + We - Fk = Em - Ef
- ¹/₂ * K * x² + m*g*h - F*d = 0 - ¹/₂ * m * v²
Also the round motion part
K* x = F + We
K * x = F + m*g*h
Replacing numeric to equal the equations and find the constant
¹/₂ * K * x² = 150*9.8* 5* sin (22°) - 5150* 5 + ¹/₂*150*(1.8m/s)²
K * x² = 421.358
Now use the other equation
K * x = 515 + 150*9.8* sin(22°)
K * x = 3268.35
Both equation give x' as a
x = 0.1289 m now using in any equation can find K
K = 25351. 69 N / m
When an object falls or is dropped from rest it's initial velocity is zero.
Using the equations for a motion in straight line. I can find the time it takes to reach 3.0 m down (half way).
x = vt - 4.9t²
-3 = 0 - 4.9t²
-3/-4.9 = t²
0.6122 = t²
0.7825 sec = t
v = v - gt
v = 0 - 9.8(0.7825)
v = -7.67 m/s
the negative denotes downward direction.
You could also solve the problem using potential and kinetic energy.
Since it starts with maximum PE and gets converted to KE when it hits the ground. mgh = mv²/2
mass cancels, use 3 meters for the halfway distance
-9.8(-3) = v²/2
29.4 * 2 = v²
√(58.8) = 7.67 m/s downwards
Answer:
limitations of the measuring instrument.
Explanation:
Hope this helps
I would say 5.6 to the 4 and I’ll I did was add it to both side