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3 years ago

12

Alexander calders mobiles, like untitled, move when air currents move through them, making them_____________

1 answer:

yanalaym [24]3 years ago

4 0

Alexander Calders mobiles, like untitled, move when air currents move through them, making them kinetic. Alexander Calder was an American artist, famous for his abstract sculpture, hanging mobiles, and Kinetic art. Kinetic art is the <span>art that depends on motion for its effect. The kinetic art's works of Alexander Calders were called "mobiles".</span>

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How are force, mass and acceleration related?

Zepler [3.9K]

Newton's 2nd law of motion:

F = ma

F is force, m is mass, and a is acceleration.

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3 years ago

A 70-kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.3 m/s. Neglect air resistan

yKpoI14uk [10]

Answer:

$h_{B} = 6.083\,m$

Explanation:

Let assume that pole vaulter begins running at a height of zero. The pole vaulter is modelled after the Principle of Energy Conservation:

$K_{A} = K_{B} + U_{g,B}$

$\frac{1}{2}\cdot m \cdot v_{A}^{2} = \frac{1}{2}\cdot m \cdot v_{B}^{2} + m\cdot g \cdot h_{B}$

The expression is simplified and final height is cleared within the equation:

$\frac{1}{2}\cdot (v_{A}^{2} - v_{B}^{2}) = g\cdot h_{B}$

$h_{B} = \frac{(v_{A}^{2}-v_{B}^{2})}{2\cdot g}$

$h_{B} = \frac{[(11\,\frac{m}{s} )^{2}-(1.3\,\frac{m}{s} )^{2}]}{2\cdot (9.807\,\frac{m}{s^{2}} )}$

$h_{B} = 6.083\,m$

5 0

3 years ago

Two conducting spheres are each given a charge Q. The radius of the larger sphere is three times greater than that of the smalle

Vinil7 [7]

Answer:

1/9 of that just outside the smaller sphere

Explanation:

The electric field strength produced by a charged sphere outside the sphere itself is equal to that produced by a single point charge:

$E=k\frac{Q}{r^2}$

where

k is the Coulomb's constant

Q is the charge on the sphere

r is the distance from the centre of the sphere

Calling R the radius of the first sphere, the electric field just outide the surface of the first sphere is

$E_0=k\frac{Q}{R^2}$

The second sphere has a radius which is 3 times that of the smaller sphere:

$R'=3R$

So, the electric field just outside the second sphere is

$E'=k\frac{Q}{R'^2}=k\frac{Q}{(3R)^2}=\frac{1}{9}(k\frac{Q}{R^2})=\frac{E_0}{9}$

So, the correct answer is 1/9.

7 0

3 years ago

An object goes from 10 m/s to 2 m/s in 2 seconds, what's its acceleration?

Mila [183]

Answer:

a=(v-u)÷t

a= (2-10)÷2

a= -8÷2

a= -4 m/s²

6 0

3 years ago

A bullet is dropped into a river from a very high bridge. At the same time, another bullet is fired from a gun straight down tow

anastassius [24]

Answer:

Option (c)

Explanation:

Both the bullets have same acceleration because they both falls under the influence of acceleration due to gravity.

The bullet which is fired from the gun has some initial velocity but the bullet which is dropped has zero initial velocity.

the acceleration is acting on both the bullets which is equal to the acceleration due to gravity and they both in motion in the influence of gravity.

8 0

3 years ago