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3 years ago

12

Alexander calders mobiles, like untitled, move when air currents move through them, making them_____________

1 answer:

yanalaym [24]3 years ago

4 0

Alexander Calders mobiles, like untitled, move when air currents move through them, making them kinetic. Alexander Calder was an American artist, famous for his abstract sculpture, hanging mobiles, and Kinetic art. Kinetic art is the <span>art that depends on motion for its effect. The kinetic art's works of Alexander Calders were called "mobiles".</span>

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Instructions Write a program that inputs the length of two pieces of fabric in feet and inches (as whole numbers) and prints the

diamong [38]

Answer:

The code is written in python in the explanation section below

Explanation:

a_feet = int(input("Input the feet of the first fabric: "))

a_inches = int(input("input the size in inches for the first piece of fabric: "))

b_feet = int(input("input the size in Feet for the second piece of fabric: "))

b_inches = int(input("Enter the size in Inches for the second piece of fabric: "))

sum_inches = a_inches + b_inches

inches_to_feet = sum_inches // 12

rem_from_div = sum_inches % 12

sum_feet = a_feet + b_feet + inches_to_feet

print("Feet: {} Inches: {}".format(sum_feet, rem_from_div))

4 0

3 years ago

Why can even a small injury to the cornea have a major effect on vision?

Rudik [331]

Your eyes are the most delicate thing on your body. Little things can make you go blind

8 0

3 years ago

A tank has the shape of an inverted circular cone with height 16m and base radius 3m. The tank is filled with water to a height

rewona [7]

Answer:

$W=17085KJ$

Explanation:

From the question we are told that:

Height $H=16m$

Radius $R=3$

Height of water $H_w=9m$

Gravity $g=9.8m/s$

Density of water $\rho=1000kg/m^3$

Generally the equation for Volume of water is mathematically given by

$dv=\pi*r^2dy$

$dv=\frac{\piR^2}{H^2}(H-y)^2dy$

Where

y is a random height taken to define dv

Generally the equation for Work done to pump water is mathematically given by

$dw=(pdv)g (H-y)$

Substituting dv

$dw=(p(=\frac{\piR^2}{H^2}(H-y)^2dy))g (H-y)$

$dw=\frac{\rho*g*R^2}{H^2}(H-y)^3dy$

Therefore

$W=\int dw$

$W=\int(\frac{\rho*g*R^2}{H^2}(H-y)^3)dy$

$W=\rho*g*R^2}{H^2}\int((H-y)^3)dy)$

$W=\frac{1000*9.8*3.142*3^2}{9^2}[((9-y)^3)}^9_0$

$W=3420.84*0.25[2401-65536]$

$W=17084965.5J$

$W=17085KJ$

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4 0

3 years ago

An object has a mass of 7 kg and is accelerating at 4 m/s2. How far would the object move if it took 168 J of work to move it?

KIM [24]

Answer:

6m

Explanation:

use work =force×distance

6 0

3 years ago

What are the conditions necessary for a terrestrial planet to have a strong magnetic field?.

Stells [14]

Both a molten metallic core and reasonably fast rotation.

6 0

3 years ago