Alexander calders mobiles, like untitled, move when air currents move through them, making them_____________
1 answer:
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Answer:
the time taken for the ball to hit the ground is 0.424 s
Explanation:
Given;
velocity of the ball, u = 5 m/s
height of the house which the ball was kicked, h = 3m
Apply kinematic equation;
h = ut + ¹/₂gt²
where;
h is height above ground
u is velocity
g is acceleration due to gravity
t is the time taken for the ball to hit the ground
Substitute the given values and solve for t
3 = 5t + ¹/₂(9.8)t²
3 = 5t + 4.9t²
4.9t² + 5t -3 = 0
a = 4.9, b = 5, c = -3
Solve for t using formula method
The amount of charge enters (and leaves) is 12 Coulomb.
<h3 /><h3>How can we find the value of the amount of charge enters (and leaves)?</h3>Here we are using the formula,
and
We are given,
P = Power of the light bulb = 25 Watt.
V = The amount of voltage where the light bulb operated = 120 Volt.
t= The time when charge enters (and leaves) the light bulb = 1.0 min = = 60 S
We have to find,
I= The amount of current flows in the light bulb.
Q= The amount of charge enters (and leaves) the light bulb.
Now we substitute the values of known parameters in the first equation, we find that,
Or,
The amount of current flows in the light bulb is 0.20 Ampere.
Now, we put the value of I in the second equation,
Or,
So, from the above calculations we can see that the amount of charge enters (and leaves) the light bulb is 12 Coulomb.
Learn more about the light bulb:
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